HBr can be added to alkenes in either the absence or presence of peroxides (producing either the Markovnikov or the anti-Markovn
ikov addition product). What intermediates leading to the formation of the major product are observed when 1-butene is treated with 1) HBr or 2) HBr/peroxides?
1 answer:
Answer:
1) 2-bromobutane
2) 1-bromobutane
Explanation:
In the HBr reaction, we will have a <u>markovniknov reaction</u> due to the <u>carbocation formation</u>. The Br- then would be added in the <u>most substituted</u> carbon of the double bond.
In the HBr/peroxide reaction we have the opposite case: an <u>anti-markovnikov reaction</u>. Therefore the Br- would be added in the <u>least substitued</u> carbon of the double bond.
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Answer:
2 moles
Explanation:
Let us first start by calculating the molecular mass of Al₂O₃.
The mass of a mole of any compound is called it's molar mass. 1 molar mass 6.02 X 10²³, or Avogadro's number, of compound entities.
Say, 1 mole of Al₂O₃ has 6.02 X 10²³ of Al₂O₃ molecules/atoms. It also has 2*6.02 X 10²³ number of Al atoms and 3*6.02 X 10²³ number of O atoms.
Molecular mass of Al : 26.981539 u
Molecular mass of O: 15.999 u
Therefore, molecular mass of Al₂O₃ is:
= u
= 101.960078 u
This can be approximated to 102 u.
1mole weighs 102 u
So, 2moles will weigh 2*102 = 204 u