All categories

3 years ago

1131 divided by 29 \

Mathematics

2 answers:

Goshia [24]3 years ago

8 0

Answer:39

Hope it helps :)

Lady_Fox [76]3 years ago

8 0

It’s 39 i hope this helped you

You might be interested in

Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200

-Dominant- [34]

Answer:

1348 light years.

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.

$(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)$

Upon substituting our given values in above formula we will get,

$x^2=1200^2+1700^2-2*1200*1700*cos (52^o)$

$x^2=1440000+2890000-4080000*0.615661475$

$x^2=4330000-2511898.81933008$

$x^2=1818101.18066992$

Let us take square root of both sides of our equation.

$x=\sqrt{1818101.18066992}$

$x=1348.3698234\approx 1348$

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0

3 years ago

Use synthetic division to determine if x+2 is a factor of f(x)=5x2+13x+6

Karolina [17]

Answer:

x+2 is a factor of $f(x) = 5x^2 + 13x + 6$

Step-by-step explanation:

To check: If (x+2) is a a factor of the polynomial $f(x) = 5x^2 + 13x + 6$

We need to check if x = -2 is the FACTOR of the given polynomial.

⇒ To show: f (-2) = 0

Now

$f(-2) = 5(-2)^2 + 13(-2) + 6\\=5(4) -26 + 6\\= 20 + 6 - 26\\= 26 - 26 = 0\\\implies f(-2) = 0$

Since, f(-2) = 0

⇒ -2 is the ROOT of the Polynomial f(x).

⇒(x +2) is the factor of the given polynomial.

Hence, x+2 is a factor of $f(x) = 5x^2 + 13x + 6$

4 0

3 years ago

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

If you can answer these simple questions im giving brainly :)

Lisa [10]

Answer:

65 3 46

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Select the three ratios that are equivalent to 3 boys/5 girls.

Stels [109]

$\dfrac{3\ boys}{5\ girls}\to\dfrac{3}{5}\\\\\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\\\\\dfrac{15}{25}=\dfrac{15:5}{20:5}=\dfrac{3}{5}\\\\\dfrac{9}{15}=\dfrac{9:3}{15:3}=\dfrac{3}{5}\\\\\dfrac{30}{50}=\dfrac{30:10}{50:10}=\dfrac{3}{5}\\\\Answer:\\\\\boxed{\dfrac{3\ boys}{5\ girls}=\dfrac{15\ boys}{25\ girls}=\dfrac{9\ boys}{15\ girls}=\dfrac{30\ boys}{50\ girls}}$

6 0

3 years ago

Read 2 more answers