please help :( I know that
lt="2^\frac{6}{5}" align="absmiddle" class="latex-formula"> is the same as
![2\sqrt[5]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B5%5D%7B2%7D)
but I don't understand how to get
![2\sqrt[5]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B5%5D%7B2%7D)
from

1 answer:
Answer:
![\displaystyle 2^{\frac{6}{5}}=2\sqrt[5]{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5E%7B%5Cfrac%7B6%7D%7B5%7D%7D%3D2%5Csqrt%5B5%5D%7B2%7D)
Step-by-step explanation:
<u>Fractional Exponents</u>
An expression like

can be expressed as a radical of the form:
![\sqrt[m]{a^n}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Ba%5En%7D)
We have the expression:

Its equivalent radical form is:
![\displaystyle 2^{\frac{6}{5}}=\sqrt[5]{2^6}](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5E%7B%5Cfrac%7B6%7D%7B5%7D%7D%3D%5Csqrt%5B5%5D%7B2%5E6%7D)
Since the exponent is greater than the index of the radical, we can take 2 out of it by following the procedure:
![\sqrt[5]{2^6}=\sqrt[5]{2^5\cdot 2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E6%7D%3D%5Csqrt%5B5%5D%7B2%5E5%5Ccdot%202%7D)
Taking out
from the radical:
![\sqrt[5]{2^6}=2\sqrt[5]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E6%7D%3D2%5Csqrt%5B5%5D%7B2%7D)
Thus:
![\displaystyle 2^{\frac{6}{5}}=2\sqrt[5]{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5E%7B%5Cfrac%7B6%7D%7B5%7D%7D%3D2%5Csqrt%5B5%5D%7B2%7D)
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