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Viktor [21]
3 years ago
7

First to answer correct will be the baranist .the ratio of students who wear spectacles is 2:5.

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

1) Who wear: 2:5

Whi don't wear: 3:5

2) 10 don't wear spectacles

3) 25

Hope it helps!!!

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Three times a number plus three times a second number is fifteen. Four times the first plus twice the second number is fourteen.
Alexxx [7]

Answer:

x = 2 | y = 3. ( 2,3 )

Step-by-step explanation:

2(3x + 3y = 15)

6x + 6y = 30

3(4x + 2y = 14)

12x + 6y = 42

- 6x. -6y. -30

6x = 12

÷ 6. ÷6

x = 2

3x + 3y = 15

3(2) + 3y = 15

6 + 3y = 15

-6. -6

3y = 9

÷3. ÷3

y = 3

3 0
3 years ago
Please awnser this is due in the morning
Anna007 [38]

where is the question

5 0
3 years ago
Tim and Tom are painters. Tim and Tom are painting a crate. Tom paints 10 sq ft per minute. They painted a particular crate in 1
slava [35]
Tom-------------- >10 sq ft per minute

Tim------------------- >3.5*10=35 sq ft per minute

 Both painters (10+35)=45 sq ft per minute

 let's assume a cubic unit crate----------> V1=1*1*1=1 feet3

<span>the total surface of the cube is S1=6*(1*1)=6 </span>sq ft

 if the volume of the cube increases twice 

V2=2 feet3 ------------------- >    2=x*x*x------------- >x=2^(1/3)

And the S2=6*(2^(1/3)*<span> 2</span>^(1/3)=9.5244 sq ft

V2/V1=9.5244/6=1.5874

Therefore

If Tim and Tom----------------------- > take 1 day----------- > to paint a crate V1

For the crate V2------------- > take 1.5874 days 

assuming an 8-hour work day

 0.5874*8=4.70 hr-------------- > 4 h 42 min

 The answer is 1 day 4h 42 min

6 0
4 years ago
What is 7.8 × 10^5 m/h in kilometers per day?
Sidana [21]

(7.8 x 10⁵ meter/hour) x (24 hour/day) x (1 kilometer / 1,000 meter) =

[ (7.8 x 10⁵ x 24 x 1) / (1,000) ] x [ kilometer / day ] = 18,720 km/day

4 0
4 years ago
Find the ninth term of the
pantera1 [17]

Answer:

a_{9}=0.00015241579

Step-by-step explanation:

Use the formula for geometric sequences:

a_{n}=a_{1}r^{n-1}

Substitute 1 in for a_{1}, -1/3 in for r, and 9 in for n

a_{9}=(1)(-1/3^9-1)

a_{9}=(1)(-1/3^8)

a_{9}=(1)(0.00015241579)

a_{9}=0.00015241579

Hope this helps! :)

5 0
3 years ago
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