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3 years ago

15

Alex types 3 pages in the same amount of time that Erica types 4.5 pages. If Alex and Erica start typing at the same time, how m

any pages will Erica have typed when Alex has 11 psges?

1 answer:

Archy [21]3 years ago

7 0

Answer:

12.5

Step-by-step explanation:

4.5 - 3 = 1.5, so 11 + 1.5 = 12.5

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What is the answer to <br> 6+0.10x=0.15x+8

asambeis [7]

Let's solve this problem step-by-step.

6+0.1x=0.15x+8

Step 1: Simplify both sides of the equation.

0.1x+6=0.15x+8

Step 2: Subtract 0.15x from both sides.

0.1x+6−0.15x=0.15x+8−0.15x

−0.05x+6=8

Step 3: Subtract 6 from both sides.

−0.05x+6−6=8−6

−0.05x=2

Step 4: Divide both sides by -0.05.

-0.05x/-0.05=2/-0.05

So, the answer for this problem is x=-40

4 0

4 years ago

Select the correct answer. Simplify the expression.<br> (see the screenshot)

Sliva [168]

Answer:

Option D

Step-by-step explanation:

Given expression has been given as,

$\sqrt[5]{224x^{11}y^8}$

$\sqrt[5]{224x^{11}y^8}=\sqrt[5]{2\times 2\times 2\times 2\times 2\times 7(x^{11})(y^8)}$

$=\sqrt[5]{(2^5)\times (7)(x^{10}\times x)(y^5\times y^3)}$

$=2^{\frac{5}{5}}\times 7^{\frac{1}{5}}\times x^{\frac{10}{5}}\times x^{\frac{1}{5}}\times y^{\frac{5}{5} }\times y^{\frac{3}{5} }$

$=2\times 7^{\frac{1}{5}}\times x^2\times y\times x^{\frac{1}{5} }\times y^{\frac{3}{5} }$

$=2x^2y\sqrt[5]{7xy^3}$

Option D will be the answer.

7 0

3 years ago

PLEASE ANSWER THEMM!!!!

natita [175]

Answer:

a.) b⁷÷b⁴

= <u>b⁷</u>

b⁴

= b^7-4

= b³

b.) <u>x </u><u> </u><u>×</u><u> </u><u> </u><u>x⁵</u>

x² × x

= <u>x</u><u>^</u><u>1+</u><u>5</u>

x^2+1

= <u>x⁶</u>

x³

= x^6-3

= x³

5 0

2 years ago

HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r

lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression $2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)$

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

$= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\$

Then we find the LCM of the resulting function

$= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\= \frac{7x}{10} + 2\frac{1}{2}y+6\\$

The final expression gives the required answer

7 0

3 years ago

The sum of the ages of my 3 children is 45 years.

Margaret [11]

I think A, but im not 100% sure

7 0

3 years ago