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Anni [7]
3 years ago
6

A scale on a map shows that 2.52.52, point, 5 centimeters represents 151515 kilometers.

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

  105 km

Step-by-step explanation:

Written as a proportion, the ratio of km to cm will be the same for both distances:

  (x km)/(17.5 cm) = (15 km)/(2.5 cm)

  x km = (15 km)(17.5/2.5) = 105 km

105 actual kilometers are represented by 17.5 cm on the map.

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sattari [20]
Y=-5x-2 
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Draw line.
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5 0
3 years ago
A football team plays in a large stadium. With a ticket price of ​$17​, the average attendance at recent games has been 50,000.
Verizon [17]

Answer:

a. N(x) = 50000 - 200x

b. R(x) = (50000-200x)(17+x)

Step-by-step explanation:

a. Given,

The the original price of each ticket = $ 17,

Also, the average attendance = 50,000

Let x be the number of times the original price of each ticket is increased by $ 1,

Also, for each​ $1 increase in the ticket​ price, attendance decreases by 200,

Thus, decrements in the attendance = 200x,

If N(x) represents the new average attendance,

Then,

N(x) = 50000 - 200x

Which is the required function,

b. Now,

Revenue = average attendance × price of each ticket

R(x) = N(x) × ( 17 + x )

⇒ R(x) = (50000-200x)(17+x)

Which is the required function.

3 0
3 years ago
How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
2 years ago
Line segment AB has a length of 4 units. It is translated 2 units to the right on a coordinate plane to obtain line segment A′B′
olchik [2.2K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Pl help I will give you brain lies
antiseptic1488 [7]
Y = 6, x = 5 y = 6, x = 5 y = 6, x = 5
3 0
3 years ago
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