Hypotenuse of the right triangle: h=sqrt(4^2+6^2)
h=sqrt(16+36)
h=sqrt(52)
h=sqrt(4*13)
h=sqrt(4) sqrt(13)
h=2 sqrt(13)
Total Area: T.A.=2*(4*6/2)+[4+6+2 sqrt(13)] (8)
T.A.=2*(12)+[10+2 sqrt(13)](8)
T.A.=24+(10)(8)+[2 sqrt(13)](8)
T.A.=24+80+16 sqrt(13)
T.A.=104+16 sqrt(13)
Answer:
( 104+16 sqrt(13) )
Hi, i hope this helps! The coordinates are (6,6). I figured this out by plotting the given points and remembering that a rectangle has parallel sides and right angles :))
Answer:
12 units²
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A =
h (b₁ + b₂ )
where h is the perpendicular height and b₁, b₂ the parallel bases
Here h = 4 ( perpendicular distance between the bases ) and
b₁ = SR = 2, b₂ = TA = 4 , then
A =
× 4 × (2 + 4) = 2 × 6 = 12 units²
First find the factors of 20
1 & 20
2 & 10
4 & 5
-1 & -20
-2 & -10
-4 & -5
Now find the pairs that have a difference of 1
-4 & -5
4 & 5
Answer: 1.9
Step-by-step explanation:
Question 11
9.88 rounds to 10
5.2 rounds to 5
10/5 = 2