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3 years ago

The length of a rectangle is three times the width. The area of the rectangle is 108 sq. inches what’s the triangles width?

Mathematics

2 answers:

MissTica3 years ago

8 0

Step-by-step explanation:

L = 3W

Area, A = L x W = 108 in2

Substitute L = 3W into the area equation, you get

A = 3W x W = 108

3W2 = 108

W2 = 108 / 3 = 36

W = √36 = 6 in

omeli [17]3 years ago

4 0

Answer:ÑÑÑÑÑÑÑÑÑññÑÑÑÑññññññÑÑÑÑÑÑÑÑÑñÑÑÑÑññ

Step-by-step explanation:

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tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

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Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

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Multiplying, we get,

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Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

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