6 treats in each bag.
First, since there were 3 batches of 24 treats, multiply 3 by 24 to get the total amount of treats
3•24=72 treats in total
Next, divide 72 by 12 to get how many treats will go in each bag.
72/12= 6 treats in each bag.
Next,
Answer:
Step-by-step explanation:
Let the number of cars be x and buses be y
<u>Then we have below inequalities as per given:</u>
- 5x + 32y ≤ 1310
- x + y ≤ 135
It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income
<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>
<u>Substitute it in the first one:</u>
- 5(135 - y) + 32y ≤ 1310
- 675 - 5y + 32y ≤ 1310
- 27y ≤ 1310 - 675
- 27y ≤ 635
- y ≤ 635/27
- y≤ 23.5
The greatest number of buses is 23
Option D. 23 is correct
Do you need me to give you word problems?
Or...
Volume = Length * Breadth * Height
Volume = 15 * 8 *3 = 360
Volume = 360 Cubic meters.
