Which equation would you use to solve the following situation?
1 answer:
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A rose costs $2.5 and a carnation costs $3.
Step-by-step explanation:
Let,
Roses = x
Carnations = y
According to given statement;
8x+10y=50 Eqn 1
6x+12y=51 Eqn 2
Multiplying Eqn 1 by 6;
Multiplying Eqn 2 by 8;
Subtracting Eqn 3 from Eqn 4;
Dividing both sides by 36;
Putting y=3 in Eqn 3;
Dividing both sides by 48;
A rose costs $2.5 and a carnation costs $3.
Keywords: linear equations, subtraction
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AB = 24
BC = 45
AC = 51
cos C = adjacent / hypotenuse
cos C = BC / AC
cos C = 45/51
BC = 45
AC = 51
cos C = adjacent / hypotenuse
cos C = BC / AC
cos C = 45/51