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3 years ago

Thanks! Help is appreciated

Mathematics

2 answers:

kifflom [539]3 years ago

5 0

Answer:

Anita only compared the values in the row for z

Step-by-step explanation:

Srry if u think i stole answer from other person who answered but my laptop is not letting me comment on that question

Viefleur [7K]3 years ago

3 0

Answer:

Step-by-step explanation:

sorry if i am incorrect but that is my best guess

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Help with this question please

riadik2000 [5.3K]

It is : D

Hope this helps

3 0

3 years ago

Use elimination to solve each system if equation 3x+2y=0and x-5y=17

kotykmax [81]

Answer:

$y = -3$

$x=2$

Step-by-step explanation:

$3x + 2y = 0$

$x - 5y=17$

to use the elimination you have to make one of the numbers same

$3(x-5y=17)$

and you would have to change the sign so that both of the 3x could cancel out.

New system of equation

$3x + 2y = 0$

$-3x+15y=-51$

$17y=-51$

$y = -3$

so we know the y value so now you could find the x value take one equation

$x - 5y=17$

$x +15=17$

$x = 2$

you could try it with both of the equations

$3x + 2y = 0$

$3x + - 6=0$

$3x-6=0$

$3x=6$

$x=6/3$

$x=2$

6 0

4 years ago

What is equivalent to the square root of 8?

Pavlova-9 [17]

It would be 2 root 2
bc it simplifies to root 2 and root 4
root 4 simplifies to 2
so its 2√2

5 0

4 years ago

Find the first five terms of each geometric sequence described <br><br> A1=1 R=4

xenn [34]

$\bf n^{th}\textit{ term of a geometric sequence}
\\\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
r=\textit{common ratio}\\
a_1=\textit{first term}\\
-------\\
a_1=1\\
r=4
\end{cases}\\\\
-----------------------------\\\\
$

$\bf \begin{array}{ccllll}
term&value\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1&a_1=1\\
2&a_2=a_1\cdot 4^{2-1}\\
3&a_3=a_1\cdot 4^{3-1}\\
4&a_4=a_1\cdot 4^{4-1}\\
5&a_5=a_1\cdot 4^{5-1}\\
\end{array}$

3 0

3 years ago

Solve the quadratic equation by completing the square. x^2+14x+47=0. What is the form and solution?

Phoenix [80]

To complete a square for ax²+bx+c, you first make a=1.
in this case, a is already 1
move c to the right side: x²+14x=-47
next, add (1/2 of b)² to both sides, in this case, b=14, half of 14 is 7, so x²+14x+ 7²=-47+7²
the left side is now a perfect square: (x+7)²=2
x+7=√2 or x+7=-√2
x=√2-7, or x=-2-√7

4 0

3 years ago