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2 years ago

2+2+1,000,000,000,000,000,000,000,000,000,000+54=

Mathematics

1 answer:

Alika [10]2 years ago

3 0

1,000,000,000,000,000,000,000,000,000,059 is the answer. Hope I helped!

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A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following

kiruha [24]

Answer:

After 47 days she will have more than 90 trillion pennies.

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

$1,2,4,8,16,32,.....$

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

$S_n=\dfrac{a(r^n-1)}{r-1}$

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

$\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}$

$\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}$

$\Rightarrow 90\times 10^{12}\le 2^n-1$

$\Rightarrow 2^n\ge 90\times 10^{12}+1$

$\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)$

$\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)$

$\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}$

$\Rightarrow n \ge 46.4$

$\Rightarrow n\approx 47$

8 0

2 years ago

Write the multiple of the first even number from 11 to 20

andrew-mc [135]

Answer:

Multiples [10] - 10, 20, 30, 40, 50

Multiples [11] - 11, 22, 33, 44, and 55

Find the Even numbers of these multiples

Multiples [10]

- 10 = Even
- 20 = Even
- 30 = Not Even
- 40 = Even
- 50 = Not Even

10 × 1 = 10
10 × 2 = 20
10 × 3 = 30
10 × 4 = 40
10 × 5 = 50

Multiples [11]

- 11 = Not Even
- 22 = Even
- 33 = Not Even
- 44 = Even
- 55 = Not Even

11 × 1 = 11
11 × 2 = 22
11 × 3 = 33
11 × 4 = 44
11 × 5 = 55
11 × 6 = 66
11 × 7 = 77
11 × 8 = 88
11 × 9 = 99

Step-by-step explanation:

.... I messed up, sorry. I thought that 20 said 11

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2 years ago

Could use some help with this. Ty to all who help!

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Step-by-step explanation:

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