Answer: 0.9726
Step-by-step explanation:
Let x be the random variable that represents the distance the tires can run until they wear out.
Given : The top-selling Red and Voss tire is rated 50,000 miles, which means nothing. In fact, the distance the tires can run until they wear out is a normally distributed random variable with a
67,000 miles and a
5,200 miles.
Then , the probability that a tire wears out before 60,000 miles :
[using p-value table for z]
Hence, the probability that a tire wears out before 60,000 miles= 0.9726
hey, I'm not sure about this answer, but I think it's true, sorry
m(2g+5mk)
18L = 18,000 ML
18,000 (ML) ÷ 60 (seconds)
18,000 ÷ 60 = 300ML/sec
Answer:
1/6 is the probability for each event, so P of all three = 1/(6^3)=1/216
Step-by-step explanation: