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malfutka [58]
3 years ago
15

Write the slope e-intercept from of the equation of the line through the given point with the given slope. Please show your work

, Thank you very much.
1. through : (0,5), slope=8
Mathematics
1 answer:
Zinaida [17]3 years ago
4 0
The slope-intercept form is written under the form of
y=mx+b where m represent the slope and y represent y-intercept. In this case, we know that the m is 8, but we don't have b yet. To find the answer, substitute (0,5) into an equation where y=5 and x=0
y=mx+b
y=8x+b
5=8(0)+b
5=b, so we have the complete y-intercept form which is y=8x+b
Or
You can you this
y-y1=m(x-x1) where point (x1,y1) represent point (0,5) in this case which led to:
y-y1=m(x-x1)
y-5=8(x-0)
y-5=8x-8(0)
y-5=8x
Add 5 to each side
y-5+5=8x+5
y=8x+5 represent the slope-intercept form. Hope it help!
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Step-by-step explanation:

The constant of proportionality (k) is the value of y when x=1. The table shows that to be 38. Then the equation is ...

  y = kx

  y = 38x

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3 years ago
Determine if the following triangle is a right triangle or not using the Pythagorean Theorem Converse. Triangle with side length
Nadusha1986 [10]

Answer:

It is a right triangle

Step-by-step explanation:

Information needed:

Formula: a^2+b^2= c^2

a: leg

b: leg

c: hypotenuse

the longest side is always the hypotenuse, so 17 in

the order of legs don't matter so 8 in and 15 in

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8 0
3 years ago
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OlgaM077 [116]

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
Help find y .. slope is m=-5/8
goblinko [34]

y = 8

using the ' gradient formula' m = (y₂ - y₁)/(x₂ - x₁)

with (x₁, y₁) = (3, 3), (x₂, y₂) = (- 5, y) and m = - \frac{5}{8}

(y - 3)/( - 5 - 3) = - \frac{5}{8}

(y - 3)/(-8) = - \frac{5}{8}

multiply both sides by - 8 to eliminate fractions

y - 3 = 5

add 3 to both sides

y = 5 + 3 =8


5 0
3 years ago
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