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musickatia [10]
3 years ago
12

ONLY ARIANA FANS: Hey guys! So I know this is asking for a lot, but a girl I know was about to hit 1k (when i tell you she worke

d her a*s off for that) a guy she knew decided to falsely copyright strike all of her videos, and claimed them as his own. He faked his own su1cide twice, and harrased her. She has 60 subscribers, thanks to other channels who supported her, please subsribe to her. She came so far, only to get it destroyed. There is more info on her channel, its moonlight melodies BACKUP (no capital letters for moonlight melodies), and its a picture of ariana grande with some bubbles
Please please help her, she deserves a lot more.(Just trying to help someone out <3)
English
2 answers:
makvit [3.9K]3 years ago
6 0

Answer:

aww... poor her i definitely will!

Nikitich [7]3 years ago
5 0

Answer:

Soo sad to hear I will surely do that

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Write an informative essay on the Iditarod dogsled race... your essay will use research to describe the Iditarod's history, incl
nikdorinn [45]

Answer:

The Iditarod Trail Sled Dog Race is an annual long-distance sled dog race run in early March from Anchorage to Nome, entirely within the US state of Alaska. Mushers and a team of 14 dogs, of which at least 5 must be on the towline at the finish line, cover the distance in 8–15 days or more.

Explanation:

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Which revision, if any, best fixes the bolded (capitalized, in this case) part of the sentence?
Anna [14]

to my knowledge It would be A

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motikmotik

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Read 2 more answers
Stainless steel rod has a gap of 0.0371 mm between its end and a rigid wall. The modulus of elasticity E = 210 GPa. The coeffici
alexgriva [62]

Answer:

The value of stress in the rod is 220.9 MPa

Explanation:

As the data is not complete, a similar question is found online and the missing data is used from that question. Similar question is attached herewith.

From the given data

The allowed total strain is given as \delta_a=0.0371 mm

The length of the rod is missing in this data which in the additional data is l=290 mm

The Modulus of Elasticity is given as E=210 GPa

The coefficient of thermal expansion is given as α= 10 ×10⁻⁶ mm / mm⋅°C.

The initial temperature is room temperature which is given as T1=22C

The final temperature is given as T2=140 C

The strain due to stress is given as

\delta_s=\dfrac{\sigma l}{E}

\delta_s=\dfrac{\sigma (0.290)}{210\times 10^9}\\\delta_s=1.38095\sigma \times 10^{-12}

Now the thermal strain is given as

\delta_c=l\alpha \Delta T\\\delta_c=0.290\times 10 \times 10^{-6}(T_2-T_1)\\\delta_c=0.290\times 10 \times 10^{-6}(140-22)\\\delta_c=0.0003422

So now the equation of the allowed strain is given as

\delta_a=\delta_s+\delta_c\\0.0371\times 10^{-3}=1.38095\sigma \times 10^{-12}+0.0003422\\\dfrac{1.38095}{10^{12}}\sigma+0.0003422=\frac{0.0371}{1000}\\\sigma=-\dfrac{10^{12}\times \:0.0003051}{1.38095}\\\sigma=-220934863.68 Pa\\\sigma=-220.9 MPa

The negative sign indicate that the stress is compressive.

The value of stress in the rod is 220.9 MPa

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When developing a project plan, what four questions should be asked?
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Answer:

b

Explanation:

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