15 + 1 because you are using apsolute value so that negative 1 becomes a positive
Triangle ABC is an isosceles triangle.
Solution:
Given data:
∠ABC = 70° and ∠ACD = 55°
<em>If two parallel lines are cut by a transversal, then alternate interior angles are congruent.</em>
m∠BAC = m∠ACD
m∠BAC = 55°
<em>Sum of the angles in a straight line add up to 180°.</em>
m∠ACD + m∠ACB + m∠ABC = 180°
55° + m∠ACB + 70° = 180°
m∠ACB + 125° = 180°
Subtract 125° from both sides, we get
m∠ACB = 55°
In triangle ABC,
∠BAC = 55° and ∠ACB = 55°
∠BAC = ∠ACB
Two angles in the triangle are equal.
Therefor triangle ABC is an isosceles triangle.
Answer:
See below.
Step-by-step explanation:
He does not have enough to loose 2,000,000 at that point, so this whole problem is nonsense.
Answer:
As Given, x+y=w+z
To Prove: AOB is a line or x+y=180
∘
(linear pair.)
According to the question,
x+y+w+z=360
∘
∣ Angles around a point.
(x+y)+(w+z)=360
∘
(x+y)+(x+y)=360
∘
∣ Given x+y=w+z
2(x+y)=360
∘
(x+y)=180
∘
Hence, x+y makes a linear pair.
Therefore, AOB is a straight line
