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3 years ago

6

Natalie is making doll costumes. each costume has 4 buttons that cost three cents each and a zipper that cost seven cents. how m

uch does she spend on buttons and zippers for each costume

1 answer:

Tema [17]3 years ago

8 0

12 cents on buttons and 7 cents for zippers

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Simplify the following using BODMAS <br> 3p + [5 − (2p + 7q)]

enot [183]

Hopes this helps if it don’t than sorry:

Answer: p + 5 - 7q

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3 years ago

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43-44 please and thanks

KatRina [158]

The easiest way to do the fractions is is you turn them to decimals.

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You think it might be the othe way around, but it’s a negative. So if it’s -36 and -35, the -35 will be bigger. Think about the number line. -36 comes before -35.

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Riya is applying to her garden.She applies it at a rate of 25 ,000 cm^3 of mulch for every m^2 of garden space. At what rate is

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The rate in m³/m² is 40m³/m².

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A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

So

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

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3 years ago

The functions and g are defined as follows.

elena-s [515]

Answer:

- 27 and 7

Step-by-step explanation:

To obtain f(- 6) substitute x = - 6 into f(x), that is

f(- 6) = 4(- 6) - 3 = - 24 - 3 = - 27

To obtain g(- 3) substitute x = - 3 into g(x), that is

g(- 3) = - 3(- 3) - 2 = 9 - 2 = 7

6 0

3 years ago