30043——————3.0043 x 10^4
30.043—————— 3.0043 x10^1
0.0030043—————-3.0043 x 10^-3
0.30043—————-3.0043 x 10^-1
3.0043————-3.0043 x 10^0
Hope this helps please mark brainiest
Answer:
0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.
Step-by-step explanation:
We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
A service center receives an average of 0.6 customer complaints per hour.
This means that
, in which h is the number of hours.
Determine the probability that exactly four complaints will be received during the next eight hours.
8 hours means that
.
The probability is P(X = 4).


0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.
Answer:
32
Step-by-step explanation:
32 × 1 = 32
8 × 4 = 32
Therefore, the LCM is 32
Answer:
Step-by-step explanation:
Given that three airlines serve a small town in Ohio. Airline A has 52% of all scheduled flights, airline B has 27% and airline C has the remaining 21%.
Their on-time rates are 83%, 66%, and 36%, respectively.
Airlines A B C
Flights 52% 27% 21% 100%
On time rates 83% 66% 36%
Flight*online rates 43.1600% 17.8200% 7.5600% 68.5400%
Thus the above table shows the product of no of flights and on time rates.
Prob it was airline A given it left on time
= 
Answer:
Scale Factor = 3
x=45
y=75
Step-by-step explanation:
Scale Factor = 60/20 = 3
x=15*3=45
Y=25*3=75