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3 years ago

URGENT HELP !!!!!! answer correctly !!!!! Will be marking Brianliest !!!!!!!!!!!!!

Mathematics

1 answer:

anzhelika [568]3 years ago

5 0

Answer:

(-2, -6)

Step-by-step explanation:

Slope: 1

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A change purse contains a total of 35 nickels and dimes. The total value of the coins is $2.25

Montano1993 [528]

Answer: 25 nickels

10 dimes

Step-by-step explanation:

6 0

2 years ago

Please help me. Need it.

Lunna [17]

Hey There!
win 10 lose 12
win 15 lose 18

5×2=10, 6×2=12
5×3=15, 6×3=18

Hope This Helps!!!

4 0

3 years ago

Explorers on a planet with a thin atmosphere want to measure the acceleration of gravity at its surface. So they use a spring gu

Murljashka [212]

Answer:

The value of $g_s$ is $g_s=\frac{30}{21} \:\frac{m}{s^2}$ .

Step-by-step explanation:

We know that the position function is given by

$s(t)=30t-\frac{g_s}{2} t^2$

Velocity is defined as the rate of change of position. Therefore,

$v(t)=\frac{d}{dt}(s(t))$

So, the velocity function is

$v(t)=\frac{d}{dt}(s(t))\\\\v(t)=\frac{d}{dt}(30t-\frac{g_s}{2} t^2)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(30t\right)-\frac{d}{dt}\left(\frac{g_s}{2}t^2\right)\\\\v(t)=30-g_st$

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

$v(t)=30-g_st=0\\\\g_s=\frac{30}{t}$

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).

So, the value of $g_s$ is $g_s=\frac{30}{21} \:\frac{m}{s^2}$ .

5 0

3 years ago

Hurry plz what are each angles

AURORKA [14]

A.8,B.2,C.6

Step-by-step explanation:

because

X=A is Z add b is 8

8 0

3 years ago

(5/6)^4x=(36/25)^9-x, please help solve for x, and the 9-x is all superscript

stiks02 [169]

$\frac{36}{25}=\frac{6^2}{5^2}=\left(\frac{6}{5}\right)^2=\left(\frac{5}{6}\right)^{-2}\\\\therefore:\\\\\left(\frac{5}{6}\right)^{4x}=\left[\left(\frac{5}{6}\right)^{-2}\right]^{9-x}\\\\\left(\frac{5}{6}\right)^{4x}=\left(\frac{5}{6}\right)^{-2(9-x)}\iff4x=-2(9-x)\\\\4x=-2\cdot9-2\cdot(-x)\\\\4x=-18+2x\ \ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\2x=-18\ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{x=-9}$

$Use:\\a^{-n}=\left(\frac{1}{a}\right)^n\\\\\left(a^n\right)^m=a^{n\cdot m}\\\\\left(\frac{a}{b} \right)^n=\frac{a^n}{b^n}$

6 0

3 years ago

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