Answer:
D.68 is greater than 112 because 68 is greater than the benchmark 12, and 112 is less than the benchmark 12.
Answer:
The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30. Otherwise, the mean and the standard deviations holds, but the distribution will not be approximately normal.
Standard deviation 4 minutes.
This means that 
A sample of 25 wait times is randomly selected.
This means that 
What is the standard deviation of the sampling distribution of the sample wait times?

The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.
Answer:
c
Step-by-step explanation:
Answer:
No, similar figures need to have corresponding sides proportional and corresponding angles congruent.
Step-by-step explanation:
Answer:

Step-by-step explanation:
We are given the integral of:

First, we can use a property to separate a constant out of integrand:

Next, expand the expression (integrand):

Since
then it can be simplified to:

Recall the formula:

For
, we need to convert to another identity since the integrand does not have a default or specific integration formula. We know that:

We can solve for
which is:

Therefore, we can write new integral as:

Evaluate each integral, applying the integration formula:

Then add all these boxed integrated together then we'll get:

Expand 4 in the expression:

Therefore, the answer is:
