PLEASE HELP ME I need it fast don’t explain
1 answer:
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Step-by-step explanation:
The upstream speed is S / t₁, and the downstream speed is S / t₂.
If we say f is the speed of the fish in calm water, and r is the speed of the river, then:
f − r = S / t₁
f + r = S / t₂
If we say T is the time it takes to cross the river, then the speed perpendicular to the river is ℓ/T, the speed parallel to the river is r, and the overall speed is f.
Using Pythagorean theorem:
f² = (ℓ/T)² + r²
f² − r² = (ℓ/T)²
(f − r) (f + r) = (ℓ/T)²
(S / t₁) (S / t₂) = (ℓ/T)²
S² / (t₁ t₂) = (ℓ/T)²
(t₁ t₂) / S² = (T/ℓ)²
√(t₁ t₂) / S = T/ℓ
T = ℓ√(t₁ t₂) / S
Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.
Let AD=x, Since given AB=3
AD+DB=3
x+DB = 3
DB = 3-x
Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem
Since given AD=BC,let us plugin BC=x in above step.
6x=11
x=
Now we know AD=x= and given CD=√2.
Let us apply Pythagoras theorem for ΔACD
= 2.315cm