Answer:
4p+3q-3p-3q
=4p-3p+3q-3q
=p+3q-3q
=p
Step-by-step explanation:
Answer: 2 vertices
The two vertices in question are (2,0) and (5,0). These are points A and D. These two points are on the x axis, which is the line of reflection. Any point on a line of reflection does not move.
The points (0,-3) and (3,-3) are not on the line of reflection, so they do move and are reflected to another location. Refer to the diagram below.
a. 6 x 5 = 30
b. 5.6 x 5 = 28
a. 20 devided by 5 = 5.6
b. 36 devided by 5 = 7.2 (i dont know, that sounds like a pretty tall person to me)
They would be identical so it would be 114
Acceleration is simplified by assuming it is the constant -g
a=-g we integrate this with respect to time to get v...
v=-gt+C where C is the initial velocity in this case 14ft/s so
v=-gt+14 integrate again to get the height function
h=(-gt^2)/2 +14t +C we are not given an initial height so C is 0
h(t)=14t-gt^2/2 letting g=32 and neatening up a bit...
h(t)=14t-16t^2
