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Murljashka [212]
3 years ago
13

HELP PLEASE! I'll be your fan

Mathematics
2 answers:
Bond [772]3 years ago
6 0
Part a)

for extraneous solution
<span>
1 ⋅ sqrt(x+2) + 3 = 0</span>

for non extraneous solution

1⋅ sqrt(x+2)  + 3 = 6

part b) solve each equation

1⋅sqrt(x+2)+3=0 

x+sqrt(x+2)=−3 

square both sides

(sqrt(<span>x+2)</span>)^ 2 = (−3)^2 


x+2=9 

x=9−2 

x=7 

do you see why its extraneous

Irina-Kira [14]3 years ago
3 0
Hello there.
<span>
Part 1. Create two radical equations, one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model.

a√x+b+c=d
</span>
1⋅ sqrt(x+2)  + 3 = 6

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Using the continuity concept, since the lateral limits and the numeric value of the function are equal at the point in which the definition changes, the function is continuous.

<h3>What is the continuity concept?</h3>

A function f(x) is continuous at x = a if it is defined at x = a, and:

\lim_{x \rightarrow a^-} f(x) = \lim_{x \rightarrow a^+} f(x) = f(a)

The definition of the piecewise function is given by:

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Since the definition of the function changes at x = 2, and the domain of the function has no restrictions, this is the only point in which there may be a discontinuity.

The lateral limits are:

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The numeric value is:

f(2) = 1.5 x 2 = 3.

Since the lateral limits and the numeric value of the function are equal at the point in which the definition changes, the function is continuous.

More can be learned about the continuity concept at brainly.com/question/24637240

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