The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
Step One
Find z
All triangles have 180 degrees. No exceptions.
z + 47 + 90 = 180 combine like terms on the left.
z + 137 = 180 subtract 137 from both sides
z = 180 - 137
z = 43 degrees.
Step Two
Use the sine function to find y
Sin(43) = opposite side / hypotenuse
opposite side = 35
sin(43) = 35 / hypotenuse
hypotenuse = 35 / sin(43)
y = 35/0.6820
y = 51.32
Solve using cos(x)
Note this problem could have been done in a shorter way.
Cos(47) = adjacent / hypotenuse.
hypotenuse = adjacent / cos(47)
y = 35 / cos(47)
y = 35 / 0.6820
y = 51.32 Both answers agree. It is a good thing to know how to do this question both ways.
Answer:
x=30/7 or decimal x=4.28571
Step-by-step explanation:
Answer:
The answer to your question is below
Step-by-step explanation:
14) sin Ф = 32/33
sin Ф = 0.9697
Ф = 75.86°
15) sin Ф = 16/36
sin Ф = 0.444
Ф = 26.39°
16) sin Ф = 29/36
sin Ф = 0.806
Ф = 53.66°
17) cos Ф = 11/34
cos Ф = 0.324
Ф = 71.12°
18) sin Ф = 21/40
sin Ф = 0.525
Ф = 31.67°
19) cos Ф = 6/14
cos Ф = 0.429
Ф = 64.62°
20) cos Ф = 38/39
cos Ф = 0.974
Ф = 13°
B. 30 petals
there is a pattern.
