Answer:
The large sample n = 190.44≅190
The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44
<u>Step-by-step explanation</u>:
Given population proportion was estimated to be 0.3
p = 0.3
Given maximum of error E = 0.04
we know that maximum error
The 85% confidence level 
now calculation , we get
√n=13.80
now squaring on both sides n = 190.44
large sample n = 190.44≅190
<u>Conclusion</u>:-
Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44
The number of defective modems in the inventory is 20%⋅ 30 + 8%⋅ 50 = 10 (out of 80).
Note that the number of defectives in the inventory is fixed, i.e., we are not told that there
is 1
8 probability that a modem in the inventory is defective, but rather that exactly 1
8
of
all modems are defective. The probability that exactly two modems in a random sample
of five are defective is = 0.102
Answer:
D.) 7:3
Step-by-step explanation:
First, find the LCM of the numbers, which is 8.
Then divide each number by 8
56÷8=7 24÷8= 3
Then, put them in a ratio
7:3
Answer:
Step-by-step explanation:
To solve this problem we need to write the mixed fraction as a fractional number, as follows:
Then, evaluating the expression:
×
= 
→
Answer:
d
Step-by-step explanation:
