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maks197457 [2]
3 years ago
13

I WILL GIVE BRAINLIEST Given: BFCE, AB perpendicular to BE, DE perpendicular to BE,

Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

Step-by-step explanation:

From the given picture,

∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]

m∠ECA = m∠BFD [Given]

m∠ECA + m∠ACB = 180° [Liner pair of angles]

m∠BFD + m∠DFE = 180° [Liner pair of angles]

m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]

m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]

Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]

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It is recommended that adults consume at least 1,000 mg of calcium every day. One ounce of whole milk contains about 25 mg of ca
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Answer:

A= 50oz milk + 2 oz cheese

Step-by-step explanation:

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3 years ago
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Assume that there is a 4​% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit
kap26 [50]

Answer:

a) 99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b) 99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

4​% rate of disk drive failure in a year.

This means that 96% work correctly, p = 0.96

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk​ drive, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 2

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984

99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b. If copies of all your computer data are stored on four independent hard disk​ drives, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 4

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744

99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

7 0
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If the product of two numbers is positive then the two numbers must both be positive true or false
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False, a negetive and negetinve both equal positive

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Find an angle in the normal range(0 degrees to 360 degrees, or 0 to 2pi radians) whose terminal side points in the same directio
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Answer:

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Step-by-step explanation:

25pi/8 - 2pi

(25-16)pi/8

9pi/8

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$60

Step-by-step explanation:

40 text messages × .25 each = $10. Plus the $50 per month is $60.

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