Answer:
Step-by-step explanation:
From the given picture,
∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]
m∠ECA = m∠BFD [Given]
m∠ECA + m∠ACB = 180° [Liner pair of angles]
m∠BFD + m∠DFE = 180° [Liner pair of angles]
m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]
m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]
Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]
