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Sveta_85 [38]
3 years ago
11

Please help me do it on a paper. Ladder method for 5, 8 , 10

Mathematics
2 answers:
bixtya [17]3 years ago
7 0

Answer:

Gcf or Lcf, you didint state on question

AnnyKZ [126]3 years ago
3 0
......................

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The three sides of a triangle are 4cm, 6cm and 8cm.
yarga [219]

Answer:

In bold below.

Step-by-step explanation:

(a) The largest angle is opposite the largest side.

So by the Cosine Rule:

8^2 = 4^2 + 6^2 - 2*4*6 cos x

cos x =  (8^2 - 4^2 - 6^2) / (-2*4* 6)

= -0.25.

x = 104.48 degrees.

(b) Area of the triangle = 1/2 * 4 * 6 sin 104.48

= 11.62

= 3 √15.

(c)  The shortest altitude will have the longest sides as the base.

Area = 1/2 * altitude * base

3√15 = 1/2 * 8 * a

a = 3√15 / 4 cm

= 0.75√15 cm.

6 0
3 years ago
Jeremy is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is even} and let B = {the sum of
Roman55 [17]

Answer:

A ∩ B = {12}

Step-by-step explanation:

What are the possible even outcomes?  

Assuming the number cubes are 1-6,

our possible outcomes run from 2-12, but we are looking for even rolls, so A={2,4,6,8,10,12}.  

How many of those are divisible by 3?  B={12}.  

We are looking for what is in common between these, so

A ∩ B= {12}

7 0
3 years ago
Instructions: Match each equations with correct type of event.
Mazyrski [523]

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

  • P(A)P(B|A) - Dependent event
  • P(A)+P(B) - Mutually exclusive events
  • P(A and B)/P(A) - Conditional events
  • P(A) . P(B) - Independent Events
  • P(A)+P(B) -P(A and B) - not Mutually exclusive events.

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}

Hence the correct match are -

  • \mathrm{P(A)P(B|A)\rightarrow} Dependent event
  • \mathrm{P(A)+P(B)}\rightarrow Mutually exclusive events
  • \mathrm{\frac{P(A ~and ~B)}{P(A)}\rightarrow} Conditional events
  • \mathrm{P(A) . P(B)\rightarrow} Independent Events
  • \mathrm{P(A)+P(B) -P(A ~and ~B)\rightarrow} not Mutually exclusive events.

Learn more about Probability of Events here -

brainly.com/question/79654680

#SPJ10

5 0
2 years ago
I WILL GIVE A BRANLIEST!<br>What is the graph of the functions?<br> y=2*2^x<br> y=-2*5^x
tekilochka [14]
For this case what you should know is that both functions are of the potential type.
 We have then that
 y = 2 * 2 ^ x
 This function grows exponentially upwards.
 y = -2 * 5 ^ x
 This function grows exponentially downwards.
 Answer
 See attached graphics.

4 0
3 years ago
Please help fassssst
Zarrin [17]

Answer:

\dfrac{9}{2}

Step-by-step explanation:

You can do this using the quadratic equation:

x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}

We solve for both to determine the positive one:

x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}              x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}

x =\dfrac{-12+ \sqrt{144+2160}}{8}                        x =\dfrac{-12- \sqrt{144+2160}}{8}

x =\dfrac{-12+ \sqrt{2304}}{8}                                 x =\dfrac{-12- \sqrt{2304}}{8}

x =\dfrac{-12+ 48}{8}                                        x =\dfrac{-12- 48}{8}

x =\dfrac{36}{8} = \dfrac{9}{2}                                           x =\dfrac{-60}{8} = \dfrac{-15}{2}

So if you are looking for a positive solution, just take the positive one as x.

8 0
3 years ago
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