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Troyanec [42]
3 years ago
13

A regional planner employed by a public university is studying the demographics of nine counties in the eastern region of an Atl

antic seaboard state.
She has gathered the following data:

County Median Income Median Age Coastal
A $ 48,725 55.3 1
B 48,383 53.7 1
C 46,862 46.5 1
D 48,777 57.9 0
E 36,339 43.4 0
F 37,618 40.3 0
G 37,495 37.2 0
H 38,301 31.2 1
I 37,705 32.5 1

(a) Is there a linear relationship between the median income and median age? (Round your answer to 3 decimal places.) What is the Correlation?
(b) Which variable is the "dependent" variable?
(c) Use regression analysis to determine the relationship between median income and median age. (Round your answers to 2 decimal places.)
(d) Interpret the value of the slope in a simple regression equation. (Round your answers to 2 decimal places.)

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Hello!

Given the variables:

X₁: Median Age

X₂: Median Income

b) Considering it from a logical point of view, income changes with age, for example, the more experienced the worker is you would think he would get a better paying job than a younger worker who is just starting. Then the dependent variable will be the median income and the independent variable will be the median age.

a)  and c)

To see if there is a linear regression between the median income and median age you have to conduct a hypothesis test for the slope. If the slope is equal to zero, there is no linear regression between the two variables, if it is different to zero, there is a regression between the two of them:

H₀: β=0

H₁: β≠0

α: 0.05

t= \frac{b-\beta }{Sb} ~~t_{n-2}

The estimated regression equation for this regression ^Yi= 20.01 + 0.50X

The standard deviation for the slope is Sb= 0.11

t_{H_0}= \frac{0.50-0}{0.11} = 4.545

And the p-value for the test is 0.0022

The p-value is less than the level of significance I choose, so the decision is to reject the null hypothesis. You can conclude that there is a linear regression between these two variables.

The correlation coefficient between the median income and the median age is r= 0.87 ⇒ This means you could expect a positive and strong linear correlation between the two variables.

d)

The slope represents how much the variable Y is modified whenever the variable X increases one unit.

In this example: Is the modification of the population mean of the median income, when the median age increases one year.

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Next-door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know that it takes 22 h using both
FrozenT [24]

Answer:

correct answer: Bob's hose required alone 33 hours and Jim's hose required alone 66 hours

Step-by-step explanation:

Given:

Bob's hose time = 50% of Jim's hose time ⇒

⇒ Jim's hose time = 2 · Bob's hose time

Let be x  Bob's hose time and  2x Jim's hose time

The following equation will solve the problem:

1/x + 1/ 2x = 1/22  

The common denominator for both fractions is 2x, so we will multiply the first fraction by the number 2 and get:

2/2x + 1/2x = 1/22 ⇒ 3/2x = 1/22 ⇒ x = 3 · 22 / 2 ⇒ x = 3 · 11 = 33 hours

Bob's hose time x = 33 hours and

Jim's hose time 2x = 66 hours

God is with you!!!

4 0
3 years ago
(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col
Ne4ueva [31]

Answer:

a) n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=16 represent the population standard deviation

n represent the sample size  

Solution to the problem

Part a

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (b) we got:

n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

ME=z_{\alpha/2}\frac{s}{\sqrt{n}}    (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

5 0
3 years ago
Simplify this expression. 12x2(3x4 − 2x)
musickatia [10]

Answer:

36*x^6-24*x^3

Step-by-step explanation:

We can simplify the expressio using the product rule. The exponents will add up when multiplied with each other:

=12*x^2*(3*x^4-2*x)

=12*3*x^(2+4)-12*2*x^(2+1)

=36*x^(6)-24*x^(3)

The answer is B

36*x^6-24*x^3

6 0
3 years ago
Write an equation for this model and solve for `x`
WARRIOR [948]
The equation is -5x = 4

x = -0.8

4 0
1 year ago
The table represents the observed number of leaves y on x branches of a tree. Calculate the rate of change between 3 and 4 branc
Dennis_Churaev [7]

Answer:

<h2>25</h2>

Step-by-step explanation:

The rate of change of number of tree y on x branches of a tree is expressed as shown;

m = Δy/Δx where;

m is the rate of change

Δy is the change in number of leaves  between 3 and 4

Δx is change in number of branches  between 3 and 4

m = Δy/Δx = y₂-y₁/x₂-x₁

From table between 3 and 4, y₂ = 100, y₁ = 75, x₂ = 4, x₁ = 3

m = 100-75/4-3

m = 25/1

m = 25

<em>Hence the rate of change between 3 and 4 branches is 25</em>

5 0
2 years ago
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