Indeed!
This is a quadratic equation, and there are several ways to factor this. I will try to explain the way I do it and try to make sense of it.
2x^2-x-15 - Original Equation
Now set up an X(as I cannot draw very well in brainly it will look bad)
1 -3
\ /
/ \
2 5
This might all look very confusing so let me explain it.
First on the left side of the x, 1*2=2 which is the coefficient of the x^2 term.
The right side, -3*5=-15 which is the constant term.
What I did in the graph thing was to find 2 such pairs that line up in the graph in a way that the opposite corners multiplied and added together would = -1.
Such as the way I lined up the graph.
1*5(one of the diagonals) + 2*-3(the second diagonals)=5-6=-1 the coefficient of the middle term.
As long as you find 2 such pairs you got the answer, just write it from left it right then top to bottom.
The first ( ) would be (1x-3), the second ( ) would be (2x+5)
Now we can always switch the ( ) as in this problem we can write the answer as (x-3)(2x+5) or switch it around as (2x+5)(x-3).
Therefore the answer A is the correct answer.
**<u>If you have any questions about my explanation, simply ask me in the comment section and I will come answer. (I know my explanation here isn't the most clear so you probably will ask questions and please don't just put the answer in and be done with it, actually try to understand my explanation it will help with further questions like this.)</u>
