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Mars2501 [29]
3 years ago
5

Find the slope intercept form of the line below. PLS HELP ITS DUE IN 30 MIN

Mathematics
1 answer:
choli [55]3 years ago
6 0
Y= 6912/3.3x
hope this helped!! <3
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Answer:

5/3

Step-by-step explanation:

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Which point on the x-axis lies on the line that passes
posledela

Answer:

(2,0)

Step-by-step explanation:

For given line AB:

y-intercept = b = -2

slope = m = y₂-y₁/x₂-x₁

= -3/2-(-4) = -3/6 = -1/2

Equation of line AB:

y = (-1/2)x - 2

Finding equation of line that is parallel to line AB and passes through the point C(2,2):

Substituting the slope from line AB into the equation of the line

y = (-1/2)x + b.

Substituting the given point (-2,2) into the x and y values 2 = (-1/2)-2 + b.

Solving for b (the y-intercept) , we get b = 1

Substitute this value for 'b' in the slope intercept form equation y = (-1/2)x + 1.

For x-intercept of the line, we let y = 0

0 = (-1/2)x + 1

x = -1(-2/1)

x = +2

So, the point on the x-axis that lies on the line that passes

through point C and is parallel to line AB is (2,0).

7 0
3 years ago
Help me please answer thanks
nasty-shy [4]

Answer:

8, 2

Step-by-step explanation:

8 * 2 = 16

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The volume of an oblique pyramid with a square base is V units3 and the height is h units.Which expression represents the area o
melamori03 [73]

Answer: a) \dfrac{3V}{h}\ units^2

Step-by-step explanation:

We know that the volume of an oblique pyramid is given by :-

\text{Volume}=\dfrac{1}{3}\text{(Base Area x height) }

If the volume of an oblique pyramid with a square base is V units³ and the height is h units.

Then, we have

V=\dfrac{1}{3}\text{(Base Area x h) }

Multiply 3 on both sides , we get

3V=\text{(Base Area x h) }

Divide both sides by h , we get

\dfrac{3V}{h}=\text{Base Area }

i.e. \text{Base Area }=\dfrac{3V}{h}\ units^2

Hence, the expression represents the area of the base of the pyramid = \dfrac{3V}{h}\ units^2

Hence, the correct answer is a) 3 v/h units^2

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3 years ago
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melamori03 [73]

Answer: 5x 5y

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