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Mars2501 [29]
2 years ago
5

Find the slope intercept form of the line below. PLS HELP ITS DUE IN 30 MIN

Mathematics
1 answer:
choli [55]2 years ago
6 0
Y= 6912/3.3x
hope this helped!! <3
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Point a pq and r are collinear on pr and pq: pr =2/3. P is located on the origin q is located at (x,y) and r is located at (-12,
dybincka [34]

The values of x and y are  8 and 0 respectively.

<em><u>Explanation</u></em>

As 'p' is located at (0,0) and 'r'  is located at (-12,0) , that means both 'p' and 'r' are on the x-axis.  So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq' = \sqrt{(x-0)^2 +(0-0)^2}= \sqrt{x^2}= x

and length of  'pr'  = \sqrt{(-12-0)^2+(0-0)^2}= \sqrt{144}=12

Given that,   pq : pr =2/3

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\frac{x}{12} =\frac{2}{3}\\ \\ 3x=24\\ \\ x= \frac{24}{3}=8

Thus, the values of x and y are  8 and 0 respectively.

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