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3 years ago

Is one flag a translation image of the other, or a rotation image? Explain.

Mathematics

2 answers:

Assoli18 [71]3 years ago

8 0

Answer: Translation

Step-by-step explanation:

The flags are a translation of each other, moving only a few coordinate points ahead but NOT changing their orientation or direction. In a rotation image, the image WILL change its orientation its held at and move the points left or right prior to their setting. In simple terms, a translation only moves the location of a image (which is true for this image), while a rotation will change its shape and rotate it into a new position.

Sources:

https://quizlet.com/395668344/geometry-b-unit-4-transformations-unit-test-flash-cards/

Afina-wow [57]3 years ago

6 0

Answer: The flag that is below the horizontal axis, is the sownward translation of the flag that is over the same axis.

Explanation:

Note that a translation transformation only moves the flag some units but does not change the direction. A rotation would have changed where the flag points (for example to the left instead of to the right).

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find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next

zalisa [80]

Answer:

The number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E is 10,080 ways

Step-by-step explanation:

We need to find the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E.

There are 9 letters in the word WONDERFUL

There is a condition that letter R is always next to E.

So, We have two letters fixed WONDFUL (ER)

We will apply Permutations to find ways of arrangements.

The 7 letters (WONDFUL) can be arranged in ways : ⁷P₇ = 7! = 5040 ways

The 2 letters (ER) can be arranged in ways: ²P₂ =2! = 2 ways

The number of ways 'WONDERFUL' can be arranged is: (5040*2) = 10,080 ways

So, the number of ways the arrangements can be made of the letters of the word'WONDERFUL' such that the letter R is always next to E is 10,080 ways

8 0

3 years ago

Three consecutive intergers have a sum of 84. Find the intergers ___,___,___,

Fudgin [204]

Answer:

27 + 28 + 29 = 84

Step-by-step explanation:

x + (x+1) + (x+2) = 84

3x + 3 = 84

84 - 3 = 81

81 / 3 = 27

8 0

4 years ago

An animal shelter has $2500 in its reserve fund. The shelter charges $40 per animal placement and would like to have at least $4

Elena-2011 [213]

Answer:

Step 1

Write and solve the inequality:

2,500 + 40a ≥ 4,000, or 40a ≥ 1,500

a ≥ 37.5

Step 2

If the shelter places 30 cats and 10 dogs,

or 40 animals, that will be enough to meet

its goal, because a = 40 is a solution to the

inequality a ≥ 37.5.

5 0

3 years ago

I am taking economics this year and I am confused about the principle of compounding . what two factors are important in making

8_murik_8 [283]

Hay i m taking econ this year to when I'm stuck i watch these they really help
https://www.youtube.com/playlist?list=PL8dPuuaLjXtPNZwz5_o_5uirJ8gQXnhEO

4 0

3 years ago

Giselle has a catering business. There is a proportional

Vanyuwa [196]

Answer:

1) The graph labeled and the ordered pairs plotted are shown in the second picture.

2) To calculate the amount of meat (in pounds) needed for a party of 75 people:

Substitute the value of the Constant of proportionality and $x=75$ into the equation $y=kx$ and then evaluate (The result is 30 pounds).

Step-by-step explanation:

<h3> The missing graph is attached.</h3>

Proportional relationships have the following form:

$y=kx$

Where "k" is the Constant of proportionality.

1) You can observe in the graph shown in the first picture this point:

$(10,4)$

So you can subsitute the coordinates of this point into $y=kx$ and solve for "k":

$4=k(10)\\\\k=\frac{4}{10}\\\\k=\frac{2}{5}$

Now you can find the amount of meat needed for 20, 30, 40, and 50 people with this procedure:

For 20 people

Substituting $k=\frac{2}{5}$ and $x=20$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(20)=8$

The ordered pair is:

$(20,8)$

For 30 people

Substituting $k=\frac{2}{5}$ and $x=30$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(30)=12$

The ordered pair is:

$(30,12)$

For 40 people

Substituting $k=\frac{2}{5}$ and $x=40$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(40)=16$

The ordered pair is:

$(40,16)$

For 50 people

Substituting $k=\frac{2}{5}$ and $x=50$ into the equation $y=kx$ and evaluating, you get:

$y=(\frac{2}{5})(50)=20$

The ordered pair is:

$(50,20)$

Knowing those values of "y"and having the ordered pairs, you can finish labeling the graph an plotting the ordered pairs (See the second picture.).

2) Substituting $k=\frac{2}{5}$ and $x=75$ into the equation $y=kx$ and evaluating, you can calculate the amount of meat (in pounds) needed for a party of 75 people. This is:

$y=(\frac{2}{5})(75)=30$

6 0

3 years ago