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Vlad [161]
3 years ago
10

On 1 st March, 2020 Mr. Mohit started a Furniture business in GANDHI NAGAR Mr. Mohit invested Rs 50,00,000.

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

Answer to the following question is as follows;

Step-by-step explanation:

Given:

Amount invested by Mr. Mohit = Rs. 50,00,000

Computation:

Books of (...... LTD)

Journal entries

Date                         Particular                        Debit        Credit

March 1         Cash                     A/C Dr.     50,00,000

                     To Capital            A/C Cr.                         50,00,000

(Being Amount invested in new business)

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cos(<em>x</em> + <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

cos(<em>x</em> - <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) + sin(<em>x</em>) sin(<em>y</em>)

==>   sin(<em>x</em>) sin(<em>y</em>) = 1/2 (cos(<em>x</em> - <em>y</em>) - cos(<em>x</em> + <em>y</em>))

Then rewrite the equation as

sin(4<em>x</em>) sin(5<em>x</em>) + sin(4<em>x</em>) sin(3<em>x</em>) - sin(2<em>x</em>) sin(<em>x</em>) = 0

1/2 (cos(-<em>x</em>) - cos(9<em>x</em>)) + 1/2 (cos(<em>x</em>) - cos(7<em>x</em>)) - 1/2 (cos(<em>x</em>) - cos(3<em>x</em>)) = 0

1/2 (cos(9<em>x</em>) - cos(<em>x</em>)) + 1/2 (cos(7<em>x</em>) - cos(3<em>x</em>)) = 0

sin(5<em>x</em>) sin(-4<em>x</em>) + sin(5<em>x</em>) sin(-2<em>x</em>) = 0

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Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Rewrite the equation again as

sin(5<em>x</em>) (2 sin(2<em>x</em>) cos(2<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) sin(2<em>x</em>) (2 cos(2<em>x</em>) + 1) = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   2 cos(2<em>x</em>) + 1 = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   cos(2<em>x</em>) = -1/2

sin(5<em>x</em>) = 0   ==>   5<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   5<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   5<em>x</em> = 2<em>nπ</em>   <u>or</u>   5<em>x</em> = (2<em>n</em> + 1)<em>π</em>

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… … … … … …    ==>   <em>x</em> = <em>π</em>/3 + <em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + <em>nπ</em>

<em />

(where <em>n</em> is any integer)

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frez [133]

Answer:

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Step-by-step explanation:

We know, the function represents 'the amount of water in the pool until it is full'.

That is, 'It is a function of time giving the value of amount of water in the pool until it is full'.

So, we get that,

The domain is representing the time in which the pool is filled completely.

As, we are given that,

Maximum time taken to completely fill the pool = 6 hours.

So, the domain of the functions is 'All real numbers between 0 and 6'.

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3 years ago
What is the solution to the equation X/2- 4 = 6? <br><br> x = 1 <br> x = 5 <br> x = 10 <br> x = 20
jeka94

[ Answer ]

\boxed{\bold{X \ = \ 20}}

[ Explanation ]

  • Solve: X ÷ 2 - 4 = 6

--------------------------

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\frac{X}{2} - 4 = 6

  • Add 4 To Both Sides

\frac{X}{2} - 4 + 4 = 6 + 4

  • Simplify

\frac{X}{2} = 10

  • Multiply Both Sides By 2

\frac{2x}{2} = 10 · 2

  • Simplify

X = 20

\boxed{\bold{[] \ Eclipsed \ []}}

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Answer:

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