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brilliants [131]
3 years ago
5

Calculate the surface area of a solid box in the shape of a cube with side length 3cm.

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

54cm^2

Step-by-step explanation:

There are 6 sides in a cube. One of the sides should have the area of 9, because it's a cube and 3 * 3 is 9.

Considering that one side is 9cm^{2}, the surface area should be 9 * 6, which is 54.

The surface area is 54cm^2.

RoseWind [281]3 years ago
6 0

Answer:

54 cm^2

Step-by-step explanation:

side ( a ) = 3 cm

Formula : -

Surface area ( cube ) = 6a^2

Surface area ( cube )

= 6 x ( 3 )^2

= 6 x 9

= 54 cm^2

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Kobotan [32]

Answer:

Fraction: 3/10

Decimal: 0.3

Percentage: 30%

Step-by-step explanation:

6 0
3 years ago
2. Find the midpoint of the segment with endpoints (1,4), (3,6)
I am Lyosha [343]

Answer:

2,5

Step-by-step explanation:

(1+3)/2, (4+6)/2

5 0
3 years ago
What is -3x^2-12x-10 in vertex form??
Alla [95]
If you type the equation on math way it will show you a graph for your answer!
5 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
Order the numbers 1.1, 0.138, 1.412 and √2 from least to greatest.
igor_vitrenko [27]
0.138, 1.1, 1.4112, and 
7 0
3 years ago
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