The height of a right cone is 3 inches shorter than the radius. What is the height of the cone if the volume is 17 cubic inches?
1 answer:
Answer:
1.03 inches
Step-by-step explanation:
Volume of a come = 1/3πr²h
If the height of a right cone is 3 inches shorter than the radius, then;
h = r - 3
Substitute
V = 1/3πr²(r-3)
Given that V = 17in^3
17 = 1/3πr²(r-3)
17*3 = 3.14r²(r-3)
51/3.14 = r²(r-3)
16.242 = r²(r-3)
r² = 16.242
r = √16.242
r = 4.03
Since h = r - 3
h = 4.03 - 3
h = 1.03 inches
hence the height is 1.03 inches
You might be interested in
Answer:
<h3><u>3/4</u></h3>
Step-by-step explanation:
1/3+5/12=3/4
You have to divide 77 by 4 and then the reminder will be 1 so only one check will be there in the final envelop.
Answer:
4.9
Step-by-step explanation:
Answer: 30 kilograms
explanation: Each 1000 grams converts to 1 kilogram
First multiply 180 and 25 which is 4500.
Then divide by 17 which should be approximately 264.71
