Question

The height of a right cone is 3 inches shorter than the radius. What is the height of the cone if the volume is 17 cubic inches?

Answer 1

Answer:

1.03 inches

Step-by-step explanation:

Volume of a come = 1/3πr²h

If the height of a right cone is 3 inches shorter than the radius, then;

h = r - 3

Substitute

V = 1/3πr²(r-3)

Given that V = 17in^3

17 = 1/3πr²(r-3)

17*3 = 3.14r²(r-3)

51/3.14 = r²(r-3)

16.242 = r²(r-3)

r² = 16.242

r = √16.242

r = 4.03

Since h = r - 3

h = 4.03 - 3

h = 1.03 inches

hence the height is 1.03 inches