Answer:
If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations. If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations.
Step-by-step explanation:
Answer:
25 Cents
Step-by-step explanation:
1 / 4 = 0.25 = 25 cents
Xy = 54
x + y = 7
















x + y = 7
3.5 + 6.45i + y = 7
- (3.5 + 6.45i) - (3.5 + 6.45i)
y = 3.5 - 6.45i
(x, y) = (3.5 + 6.45i, (3.5 - 6.45i)
or
x + y = 7
3.5 - 6.45i + y = 7
- (3.5 - 6.45i) - (3.5 - 6.45i)
y = 3.5 + 6.45i
(x, y) = (3.5 - 6.45i, 3.5 + 6.45i)
The two numbers that add up to 7 and can multiply to 54 is 3.5 ± 6.45i.
Can u show a picture what your talking about
MO = 12 and PR = 3
Solution:
Given
.
Perimeter of ΔMNO = 48
Perimeter of ΔPQR = 12
MO = 12x and PR = x + 2
<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>


Do cross multiplication.


Subtract 48x from both sides.


Divide by 96 on both sides, we get
⇒ 1 = x
⇒ x = 1
Substitute x = 1 in MO an PR.
MO = 12(1) = 12
PR = 1 + 2 = 3
Therefore MO = 12 and PR = 3.