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erica [24]
3 years ago
7

I need help please. i dont understand and please explain

Mathematics
1 answer:
ki77a [65]3 years ago
5 0

Answer:

c 82

Step-by-step explanation:

because I smart person

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I need help ASAP please
gulaghasi [49]

Answer: x =168

 

Step-by-step explanation:I think it would be 80 plus 88 so its 168.  

4 0
4 years ago
there are 16 boys and 24 girls in chorus whats the percent of the total number of students in chorus are boys?
Ipatiy [6.2K]
The percent of boys in the class is 40% because 16 + 24 = 40 (the entire amount of kids) 16 / 40 = .4 then move decimal twice to the right for percentage which gives you 40%

The answer is 40%

I hope this helped :)

5 0
3 years ago
Read 2 more answers
Which is the definition of a line segment?
Vlada [557]
In geometry, a line segment<span> is a part of a </span>line<span> that is bounded by two distinct end points, and contains every point on the </span>line<span> between its endpoints. A closed </span>line segment<span> includes both endpoints, while an open </span>line segment<span> excludes both endpoints; a half-open </span>line segment<span> includes exactly one of the endpoints.</span>
3 0
4 years ago
Lucius is making favors for his sister's wedding. If supplies for 25 favors cost $62.50, how much do supplies for 60 favors cost
dusya [7]
It will cost 150

62.50/25 = 2.5

2.5*60 =150


8 0
3 years ago
Read 2 more answers
You plan to acquire a sinusoidal signal that repeats 250 microseconds. What should be the minimum sampling rate of the digital s
Phoenix [80]

Answer: F = 25.1 kHz

Step-by-step explanation:

Time (period) = 250 × 10^-6 s

Let's first calculate the folding frequency. Given by 

NF (rad s-1) = π/Δt

where NF = Nyquist frequency

 t  = time increment between observations.

The original signal must be filtered by analog or physical methods to remove all frequencies higher than the Nyquist frequency before the signal is sampled or digitized.

F = 3.143/0.00025

F = 12566.37Hz

minimum sampling rate = 2F

2 × 12566.37 = 25132.74Hz

minimum sampling rate  = 25.1 KHz

5 0
3 years ago
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