The correct answer to this question is <span>d.) integral from 1 to 2 of (2/(x+1))
</span>To solve this:
Since Δx = 1/n.
lim (n→∞) Δx [1/(1+Δx) + 1/(1+2Δx)+ ... + 1/(1+nΔx)]
= lim (n→∞) Σ(k = 1 to n) [1/(1 + kΔx)] Δx.
x <---> a + kΔx
a = 0, then b = 1, so that Δx = (b - a)/n = 1/n
Since (1 + kΔx) combination, a = 1 so that b = 2.
Then, f(1 + kΔx) <-----> f(x) ==> f(x) = 1/x.
This sum represents the integral
∫(x = 1 to 2) (1/x) dx, so the correct answer is <span>d.) integral from 1 to 2 of (2/(x+1))
Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
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Answer:
I said C on my test but I'm pretty sure its right
Answer:50%
Step-by-step explanation:
222+222=444 so as a fraction the probability is 1/2 but as a percentage its 50%
Answer:
16
Step-by-step explanation:
24-8 = 16
hope this helps....
Answer:
109
Step-by-step explanation:
Hopw it helps :).
