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3 years ago

Roberto wrote a sentence that describes an equation.

Mathematics

2 answers:

ryzh [129]3 years ago

5 0

Answer:

x/2=45; x = 90

Step-by-step explanation:

tresset_1 [31]3 years ago

3 0

The last one: x/2=45; x = 90
the problem says: half of a number is 45.

let's use x to represent this number
we know that dividing by 2 halves a number, so, x/2 = 45

to get x alone, we multiply 2 by 2 to cancel it out. so, multiply by 2 on both sides

x/2 • 2 = 45 • 2

x = 90

hope this helped!

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In a standard deck of cards there 52 cards of which 26 are black and 26 are red. Additionally, there are 4 suits, hearts, clubs,

stich3 [128]

Using probability concepts, it is found that P(S and D) = 0.1275.

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A probability is the <u>number of desired outcomes divided by the number of desired outcomes</u>.
In a standard deck, there are 52 cards.
Of those, 13 are spades, and 13 are diamond.

The probability of selecting a spade with the first card is 13/52. Then, there is a 13/51 probability of selecting a diamond with the second. The same is valid for diamond then space, which means that the probability is multiplied by 2. Thus, the desired probability is:

$P(S \cap D) = 2 \times \frac{13}{52} \times \frac{13}{51} = \frac{2\times 13 \times 13}{52 \times 51} = 0.1275$

Thus, P(S and D) = 0.1275.

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8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.

According to that, if $a + b = 0$ , then $a = 0$ and $b = 0$ .

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3 years ago

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Answer:

Step-by-step explanation:

She has 1 in 11 chances of getting the purple one

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