<span>Twice the sum of a number and 3 = 2(n + 3)
</span><span>three times the difference of the number and 3 = 3(n - 3)
so
</span><span>Twice the sum of a number and 3 is equal to three times the difference of the number and 3:
</span>2(n + 3) = 3(n - 3)
2n + 6 = 3n - 9
n = 15
answer
2(n + 3) = 3(n - 3)
n = 15
X^2 + 12x = -6
x^2 + 12 x + 6^2 = -6 + 6^2
(x + 6)^2 = - 6 + 36
(x +6)^2 = 30
In the first step I had to add 6^2 = 36. The answer is option B. 36.
what is one easy addition equation?
1 + 1 = 2
how did you get this ?
you add 1 and 1 together and you will get your solution.
Answer: x=1,y=0
Step-by-step explanation:
X-2y=1.....equation 1
2x-y=2.....equation 2
X=1+2y.......equation 3
Substitute equation 3into 2
2(1+2y)-y=2
2+4y-y=2
2+3y=2
3y=2-2
3y=0
Y=0/3
Y=0
Substitute for y=0 in equation 1
X-2y=1
X-2(0)=1
X-0=1
X=1
X=1 & Y=0
