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3 years ago

Find the product of (3x+2)(3x+7)

Mathematics

1 answer:

Alja [10]3 years ago

6 0

Answer:

it is a quadratic equation

Step-by-step explanation:

3x(3x+7) +2(3x+7)

9x square +21x +6x+14

= 9x square +27x +14

You might be interested in

A triangle has a perimeter of 91 centimeters. Each of the two longer sides of the triangle is three times as long as the shortes

Mkey [24]

9514 1404 393

Answer:

13 cm, 39 cm, 39 cm

Step-by-step explanation:

If x is the short side, then the other two sides are 3x and 3x. The perimeter is the sum of side lengths:

x +3x +3x = 91

x = 91/7 = 13

3x = 3(13) = 39

The length of the short side is 13 cm; the other two sides are 39 cm.

4 0

2 years ago

Find the other endpoint of the line segment with the given endpoint and midpoint? Endpoint (3,1) midpoint (-10,-5)

Sav [38]

(-23,-11) is the other endpoint due to (a+b/2)

3 0

2 years ago

Please help. Flow chart proof. I'll give brainliest

AveGali [126]

Step-by-step explanation:

Statement | Reason

CB=AB Given

DBC=DBA Given

DB = DB Reflexive Property

/_\ DBC

/_\DBA SAS

Sorry for the formatting the =~ means congruent.

4 0

2 years ago

Kyle is buying turkey from the deli. If turkey cost 8.50 per kilogram and he wants 3 kilograms how much will he spend on the tur

Artemon [7]

Answer:

The answer is 25.50

Hope this helps!

6 0

2 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago