Answer: Chemical engineers use chemistry and engineering to turn raw materials into usable products, such as medicine, petrochemicals, and plastics on a large-scale, industrial setting. They are also involved in waste management and research. They may be involved in designing and constructing plants as a project engineer.
Explanation:
It’s A because it running more faster the the zebra
We are given the mass spectrum data for this compound which has a molecular ion peak of m+ = 91.043 m/z. When we have an m+ peak that is an odd number, that suggests that there are an odd number of nitrogens, in this case we'll assume 1 nitrogen atom to start. Nitrogen has a mass of 14 so we will substract that from our initial value.
91- 14 (1N) = 77 m/z
We are also told that there are carbon, hydrogens and oxygens present, so we will assume there is at least one oxygen which has a mass of 16 and subtract that value.
77 - 16 (1 O) = 61 m/z
Now we will try to get as close as possible to the remaining mass with carbons that has a mass of 12, and fill the remaining mass with hydrogens that have a mass of 1.
61 / 12 = 5
5 x 12 = 60
61 - 60 (5 C) = 1 m/z and this leaves us with 1 H.
The current formula would be C₅HON, but this structure is impossible since we do not have enough hydrogens to satisfy the carbons. So we can try to use 4 carbons instead and fill the rest with hydrogens.
4 x 12 = 48
61 - 48 (4 C) = 13 m/z and this leaves us with 13 H.
The current formula would be C₄H₁₃ON. The most hydrogens we can have in a compound is 2n+2 where n is the number of carbons. So with 4 carbons the most hydrogens we could have is 10. Therefore, our formula has too many hydrogens and also cannot work. So we cannot make up the remaining mass with carbons and hydrogens, therefore, we should add another oxygen before working with carbons and hydrogens.
61 - 16 (1 O) = 45 m/z
45/ 12 = 3.75
3 x 12 = 36
45 - 36 (3 C) = 9 m/z which gives us 9 hydrogens left.
The current formula is now C₃H₉O₂N. To test if this formula works we can calculate the double bond equivalents (DBE), also known as degrees of unsaturation.
DBE = C - H/2 + N/2 + 1 = 3 - (9/2) + (1/2) + 1 = 0
A value of 0 DBE tells us that there are no double bonds in this molecule but that the formula is a possibility so:
C₃H₉O₂N = 91 m/z
Answer: In chemistry, reactivity is the impetus for which a chemical substance undergoes a chemical reaction, either by itself or with other materials, with an overall release of energy.
Explanation:
Answer:
What will happen to Uk if you double the mass?
Explanation:
Uk = 0.5 * m * v²
You see that both m and v are variable, which means that both m and v can be any number. Regardless of the numbers you put in for m or v, the formula to calculate the kinetic energy (Uk) remains valid.
You could ask
1. What will happen to Uk if you double the mass?
2. What will happen to Uk if you double the velocity?
please see and understand(!) that the relationship between Uk an v² is indeed the velocity squared....
EXTRA
Uk = 0.5 * m * (v)²
Suppose the m = 3kg and velocity = 5 m/s
What is the Uk?
Well if you know the formula you can use your calculator to find out:
Uk = 0.5 * m * (v)²
Uk = 0.5 * 3 * (5)²
Uk = 0.5 * 3 * 25
Uk = 37.5 kgm/s²
Again you ask what will happen to Uk if you double the velocity?
At first it was 5 m/s and now it doubles, which means it now has that value *2
The new velocity is 5 *2 = 10 m/s
Uk = 0.5 * m * (v)²
Uk = 0.5 * 3 * (10)²
Uk = 0.5 * 3 * 100
Uk = 150 kgm/s²
150 = 4 * 37.5
So now you see that if you double your velocity, the Uk will be 2² = 4 times as big !
