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WARRIOR [948]
3 years ago
5

How many grams of NH4ClO4 would dissolve in 250 mL at 30 C

Chemistry
1 answer:
baherus [9]3 years ago
8 0
Ammonium perchlorate appears as a white, crystalline solid or powder. Classified as a division 1.1 explosive if powdered into particles smaller than 15 microns in diameter or if powdered into larger particles but thoroughly dried. Does not readily burn, but will burn if contaminated by combustible material. May explode under prolonged exposure to heat or fire. Used to make rocket propellants, explosives, pyrotechnics, as an etching and engraving agent, and in analytical chemistry.
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Calculate the number of gold atoms in a sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and r
Fudgin [204]

Answer: N = 2.78 × 10^23 atoms

There are N = 2.78 × 10^23 atoms in 70g of Au2cl6

Completed Question:

Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits

Explanation:

Given:

Molar mass of Au2cl6 = 303.33g/mol

Mass of Au2cl6 = 70g

Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol

According to the chemical formula of Au2cl6,

1 mole of Au2cl6 contains 2 moles of Au

Number of moles of Au = 2 × 0.231mol = 0.462mole

There are 6.022 × 10^23 atoms in 1 mole of an element.

Number of Atom of gold in 0.462 mole of gold is:

N = 0.462 mol × 6.022 × 10^23 atoms/mol

N = 2.78 × 10^23 atoms

7 0
3 years ago
Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below.
zavuch27 [327]

15.63 mol. You need 15.63 mol HgO to produce 250.0 g O_2.

<em>Step 1</em>. Convert <em>grams of O_2 to moles of O_2</em>

Moles of O_2 = 250.0 g O_2 × (1 mol O_2/32.00 g O_2) = 7.8125 mol O_2

<em>Step 2</em>. Use the molar ratio of HgO:O_2 to convert <em>moles of O_2 to moles of HgO </em>

Moles of HgO = 0.8885 mol O_2 × (2 mol HgO/1 mol O_2) = <em>15.63 mol HgO</em>

7 0
3 years ago
Read 2 more answers
A 0.2688 g sample of a monoprotic acid neutralized 16.4 mL of 0.08133 M KOH solution. Calculate the molar mass of the acid
ivanzaharov [21]

Answer:

202 g/mol

Explanation:

Let's consider the neutralization between a generic monoprotic acid and KOH.

HA + KOH → KA + H₂O

The moles of KOH that reacted are:

0.0164 L × 0.08133 mol/L = 1.33 × 10⁻³ mol

The molar ratio of HA to KOH is 1:1. Then, the moles of HA that reacted are 1.33 × 10⁻³ moles.

1.33 × 10⁻³ moles of HA have a mass of 0.2688 g. The molar mass of the acid is:

0.2688 g/1.33 × 10⁻³ mol = 202 g/mol

3 0
3 years ago
Which of the following best states the difference between an alcohol and an ether?
goldenfox [79]
I'd say it would be
D 
8 0
3 years ago
Use the table of data for a decomposition reaction to answer the question Concentration (C) at T1 (g/L) C at T2 (g/L) C at T3 (g
Alex73 [517]

Based on the nature of chemical equilibrium, the system reached equilibrium first at the time T2.

<h3>What is chemical equilibrium?</h3>

Chemical equilibrium refers to the state of a reversible chemical reaction in which the rate of forward reaction for the the formation is equal to the rate of backward reaction for the formation of reactants.

In the table of the decomposition reaction given above, the system reached equilibrium first at the time T2 when the concentration of the reactant and products were the same.

Learn more about chemical equilibrium at: brainly.com/question/5081082

4 0
2 years ago
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