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Fantom [35]
3 years ago
9

Someone please help

Mathematics
1 answer:
OleMash [197]3 years ago
4 0
Answer:

Why wont anyone help me please
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Four less than a number squared
nordsb [41]
4 < x^2 i think i dont really know im just trying to get my account verified
7 0
3 years ago
Read 2 more answers
The number y divided by 2
Goshia [24]

Answer:

what number is y?

it would be x no?

Step-by-step explanation:

5 0
3 years ago
Find the approximate solution(s) to each of the following equations graphically. Use technology to support your
ser-zykov [4K]

Answer: x" = 5.69

Step-by-step explanation:

The graphic solution is attached.

Verifying the solution:

Existence condition: x > 0

2x - 4 = √x + 5

√x =2x - 4 - 5

√x =2x - 9 (²)

x = (2x - 9)²

x = 4x² - 36x + 81

4x² - 36x - x + 81 = 0

4x² - 37x + 81 = 0

Δ = -37² - 4.4.81 = 1369 - 1296 = 73

x = 37 ±√73/8                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                          

x' = 3.55

x" = 5.69

checking:

2*3.55 - 4 = 3.1

√3.55 + 5 = 6.88 Its not the same ∴ 3.55 is not a solution

2*5.69 - 4 = 7.39

√5.69 + 5 = 7.39 ∴ it's the only solution

4 0
3 years ago
Answer is 8.99, but how tho​
Mnenie [13.5K]

Answer:

  x ≈ 8.99

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationship between trig functions and sides in a right triangle. Here, the geometry of the problem can be modeled by a right triangle. We are given one side and want to find the difference in lengths of the other side for two different angles.

__

<h3>setup</h3>

The tower height is the side opposite the angle of elevation. The distance from the tower to the end of the shadow is the side adjacent to the angle of elevation, so the relevant trig relation is ...

  Tan = Opposite/Adjacent

  tan(angle of elevation) = (tower height)/(length of shadow)

Solving for the length of shadow, we have ...

  length of shadow = (tower height)/tan(angle of elevation)

The difference in shadow lengths is 2x for the two different angles, so we have ...

  2x = 24.57/tan(30°) -24.57/tan(45°)

__

<h3>solution</h3>

Dividing by 2 and factoring out the tower height, we have ...

  x = 12.285(1/tan(30°) -1/tan(45°)) = 12.285(√3 -1)

  x ≈ 8.993244

The value of x is about 8.99.

7 0
2 years ago
Determine whether AB←→ and CD←→− are parallel, perpendicular, or neither. A(−1, −4), B(2, 11), C(1, 1), D(4, 10)
Paladinen [302]
Slope of AB
m = (y2 - y1)/(x2 - x1)
m = (11 - (-4))/(2 - (-1))
m = (11 + 4)/(2 + 1)
m = 15/3
m = 5
The slope of line AB is 5

Slope of CD
m = (y2 - y1)/(x2 - x1)
m = (10 - 1)/(4 - 1)
m = 9/3
m = 3
The slope of CD is 3

Since the two slopes are not equal, this means the lines are not parallel.
Since (slope of AB)*(slope of CD) = 5*3 = 15 is not equal to -1, this means the lines are not perpendicular

Answer: Neither (not parallel; not perpendicular)

4 0
4 years ago
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