Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))

Let A = arcsin(-5/13) = -arcsin(5/13)

Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12

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3 0

4 years ago

In a circle, what is the diameter in relation to the radius?

pogonyaev

Answer:

And by definition the radius would be lower than the diameter and we have the following relationship:

$D= 2r$

And then the best answer would be:

B 2r

Step-by-step explanation:

When we have a circle we know that the area is given by:

$A= \pi r^2$

And we also know that the diameter is the distance between two any points in the circle passing through the center.

And by definition the radius would be lower than the diameter and we have the following relationship:

$D= 2r$

And then the best answer would be:

B 2r

7 0

4 years ago

What is the x-value in the solution to this equation of linear equations? 2x-y=11 x+3y=-5

saw5 [17]

The solution to these linear equations is (4,-3)

So the x-value is 4

:)))

6 0

4 years ago

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