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3 years ago

If Log 4 (x) = 12, then log 2 (x / 4) is equal to A. 11 B. 48 C. -12 D. 22

2 answers:

8 0

If log₄ (x) = 12, then log₂ (x / 4) =?
The easiest way:

a) log₄ (x) = 12, re write it in exponential way : x = 4¹² = 16,777,216

b) Plug the value of x in log₂ (x / 4)

log₂ (16,777,216 / 4) → log₂(4,194,304)

and log₂(4,194,304) = 22

kiruha [24]3 years ago

5 0

Hi,
The answer to your problem is D. 22. Hope this helps and have a wonderful day!

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alina1380 [7]

${x}^{2} - {15}^{2} = {8}^{2} \\ \\ {x}^{2} - 225 = 64 \\ \\ {x}^{2} = 64 + 225 \\ \\ {x}^{2} = 289 \\ \\ x = 17$

8 0

3 years ago

Read 2 more answers

Calculate the following limit:

aleksklad [387]

$\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\$
$\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\$
$=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1
$

8 0

3 years ago

PLEASE HELP WITH GEOMETRY QUESTION!! FIND H

Yakvenalex [24]

Answer:

we have

when

base=8cm

height=11cm

area of parallelogram is :base×height

=8*11=88cm³

Now for

base=15cm

height=h

we have

the area of parallelogram=88cm²

base ×height=88cm²

15*h=88

h=88/15

h=88/15 or 5 13/15 or 5.86 cm in approximately

3 0

3 years ago

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Perform the indicated operation and write the result in the form a + bt.<br> (4 +9t)(7 - 4t)

bulgar [2K]

The answer is 64+47i

7 0

3 years ago

Which equation represents the vertical line passing through (7,-3)?

Nimfa-mama [501]

Answer:

x = 7

Step-by-step explanation:

The equation of a vertical line has equation of the form

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (7, - 3) with x- coordinate 7 , thus

x = 7 ← equation of vertical line

3 0

3 years ago