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galina1969 [7]
3 years ago
8

PLEASE HELP!!

Mathematics
2 answers:
Effectus [21]3 years ago
5 0

Answer:

I think nature's delight:$0.85/pound

kifflom [539]3 years ago
5 0

Answer:

Nature's Delight

Step-by-step explanation:

It offers the lowest unit for carrots.

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What is the mean for the set of data
AnnyKZ [126]

Answer:

B) 25

Step-by-step explanation:

First, you add up all the numbers. Then, you divide it by 9 which is the total amount of numbers there are.

7 0
3 years ago
The shapes below are mathematically similar​
s2008m [1.1K]

Answer:

5 cm is the answer brochacho

7 0
3 years ago
The sum of the diagonals of a rhombus is 5√2.
Alex
Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC
= \frac{1}{2} BD (AO + OC)
\frac{1}{2} BD \times AC

So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}
BD \times AC = 8
Now, AC + \: BD = 5 \sqrt{2}

Squaring both sides, we get
AC {}^{2} + BD {}^{2} + 2 AC.BD =50
AC {}^{2} + BD {}^{2} + 2 \times 8 = 50
AC {}^{2} + BD {}^{2} = 50 - 16
AC {}^{2} + BD {}^{2} = 34

In △AOB, we have
OA {}^{2} + OB {}^{2} =AB {}^{2}
( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}
\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}
AC {}^{2} + BD {}^{2} = 4 AB {}^{2}
34 = 4 AB {}^{2}

Square rooting both sides
\sqrt{34} = 2 AB
Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units.

Hope it helps!

7 0
3 years ago
已知一个质点做变速直线运动的位移函数 s  3t 2  e2t , t为时 间,则在时刻t  2处的速度和加速度分别为
Natasha2012 [34]

Answer:

can't understand language

6 0
3 years ago
flvs hope If $x^2+bx+16$ has at least one real root, find all possible values of $b$. Express your answer in interval notation.
Galina-37 [17]
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
                                           b^2-4(1)(16) ≥ 0
                                                  </span><span>b^2-64 ≥ 0
                                             (b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
5 0
3 years ago
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