Given: AB=BC,AM=MC BM ⊥AC , EF⊥BC Prove: EC/AB = FC/MA
1 answer:
Answer:
<em>9</em><em>0</em><em> </em><em>degree</em><em> </em><em>EFC</em><em>. </em><em>and</em><em>. </em><em>BMC</em>
<em>across</em><em> </em><em>fc</em><em>/</em><em>ma</em><em> </em>
<em>across</em><em> </em><em>ec</em><em>/</em><em>ab</em>
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