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2 years ago

Pleaseee help me asap

Mathematics

1 answer:

valkas [14]2 years ago

7 0

Answer:

(0,-3)

Step-by-step explanation:

You can just graph it and find the center.

Please put me as brainliest. Thank you.

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Ray wants to buy the larger of two aquariums. one aquarium has a base that is 20 inches by 20 inches and height that is 18 inche

Svetradugi [14.3K]

Ray should buy the first one because it has the greater volume by 1,440 square inches.
Tank 1: 20x20x18=7,200
Tank 2: 40x12x12=5,760
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3 years ago

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picture included , please help, which of the following equations describe the line shown below (1,10) and (-3,2) *check all that

rosijanka [135]

Slope is $\text{m}=\frac{y_1-y_2}{x_1-x_2}=\cfrac{10-2}{1-(-3)}$
Then you use the equation
$\text{y=mx+b}$
Where b is the y-intercept. To find it, plug in x and y from one of the points. Say, point 1 (1,10):
$10=m(1)+b$
You know m (from above) and now you can solve for b.

Rearrange terms:
$y-b=mx$

And that will be the answer.

Make sense?

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3 years ago

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The graph below shows the solution to which system of inequalities

Oksi-84 [34.3K]

The answer is
the option A
<span>The graph shows the solution of the system of inequalities
y> -3
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2 years ago

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"per month" means: ADD

Effectus [21]

Per month means multiply
Total means the amount your ending with but for this you could say add
Final answer f = 4.75 + 10m

3 0

2 years ago

Solve the proportion

mario62 [17]

Answer:

$\boxed{\sf x = 5}$

Step-by-step explanation:

$\sf Solve \: for \: x \: over \: the \: real \: numbers: \\ \sf \implies \frac{2}{x - 3} = \frac{5}{x} \\ \\ \sf Take \: the \: reciprocal \: of \: both \: sides: \\ \sf \implies \frac{x - 3}{2} = \frac{x}{5} \\ \\ \sf Expand \: out \: terms \: of \: the \: left \: hand \: side: \\ \\ \sf \implies \frac{x}{2} - \frac{3}{2} = \frac{x}{5} \\ \\ \sf Subtract \: \frac{x}{5} - \frac{3}{2} \: from \: both \: sides: \\ \sf \implies \frac{x}{2} - \frac{3}{2} - ( \frac{x}{5} - \frac{3}{2} ) = \frac{x}{5} - ( \frac{x}{5} - \frac{3}{2} ) \\ \\ \sf \implies \frac{x}{2} - \frac{3}{2} - \frac{x}{5} + \frac{3}{2} = \frac{x}{5} - \frac{x}{5} + \frac{3}{2} \\ \\ \sf \frac{x}{5} - \frac{x}{5} = 0 : \\ \sf \implies \frac{x}{2} - \frac{x}{5} - \frac{3}{2} + \frac{3}{2} = \frac{3}{2} \\ \\ \sf \frac{3}{2} - \frac{3}{2} = 0: \\ \sf \implies \frac{x}{2} - \frac{x}{5} = \frac{3}{2} \\ \\ \sf \frac{x}{2} - \frac{x}{5} = \frac{5x - 2x}{10} = \frac{3x}{10} : \\ \sf \implies \frac{3x}{10} = \frac{3}{2} \\ \\ \sf Multiply \: both \: sides \: by \: \frac{10}{3} : \\ \sf \implies \frac{3x}{10} \times \frac{10}{3} = \frac{3}{2 } \times \frac{10}{3} \\ \\ \sf \frac{3x}{10} \times \frac{10}{3} = \cancel{\frac{3}{10} } \times( x) \times \cancel{ \frac{10}{3} } = x : \\ \sf \implies x = \frac{3}{2} \times \frac{10}{3} \\ \\ \sf \frac{3}{2} \times \frac{10}{3} = \cancel{ \frac{3}{2} } \times \cancel{ \frac{3}{2} } \times 5 : \\ \sf \implies x = 5$

8 0

3 years ago