Answer: NO
Step-by-step explanation:
The functions that models the height of the ball is given as
h(t) = -5t2 + 40t + 100
Where
a = -5, b = 40, c = 100
The time the ball will reach the maximum height will be the vertex of the parabola. At the line of symmetry, the time t will be:
t = -b/2a
Substitute b and a into the formula above.
t = - 40 / -5 = 8
Substitute 8 for t in the function f(t)
h(t) = - 5(8)^2 + 40(8) + 100
h(t) = -5(64) + 40(8) + 100
Open the bracket
h(t) = -320 + 320 + 100
h(t) = 100
The maximum height of the ball is 100m
Given that the power lines is 185 metres above the ground. The golf ball will therefore not hit power lines because the maximum height the ball can go is 100 metres
Answer:
Caroline buys 3 packs of candles and 5 packs of holders.
Step-by-step explanation:
1.) You need to add numbers of candle packs together until they both reach the same number, for example, multiples of 30 are 30, 60, 90.
2.) Then you add multiples of the holders. 18, 36, 54, 72, 90.
3.) You find that Caroline buys 3 pakcs of candles and 5 packs of holders to have the same number of both.
As a disclaimer, I can't say I'm completely confident in this answer. Use at own risk.
Formulas:
Year 1: 328,000 (sales) - 117,000 (expense) = 211,000 (profit)
Year 2: 565,000 (sales) - x (expense) = y (profit)
Net Profit: 211,000 + y = 113,000
Math
211,000 (profit y1) + 565,000 (sales y2) = 776,000
776,000 - 113,000 (net profit) = -663,000 (expenses)
Confirm:
Net Profit: 211,000 + y = 113,000 (listed in formulas, just a reminder)
Plug in: 565,000 (y2 sales) - 663,000 (our solution) = -98,000
211,000 (y1 net) + -98,000 (our plug in) = 113,000 (2 year net profit given to us)
Step-by-step explanation:Let number of 49 cents =A
Let number of 33 cents=B
<u>A+B=45 equation 1</u>
1 $=100 cents
49 cents =.49 dollar
33 cents=.33 dollar
so .<u>49A+.33B=17.89 equation 2</u>
Add equation 1 and equation 2
since these are simultaneous equations
.49A+.33B=17.89
A+ B=45
so divide equation 2 by 100 we get
49A+33B=1789
A+B =45 multiply equation 1 by 33 on both the sides we get
<u>33A+33B=1485 equation 3</u>
so subtract equation 3 from equation 2 we get
49A+33B=1789 equation 2
<u>33A+33B=1485 equation 3</u>
<u>16A+0 =304</u>
16A=304
A=304/16
A=19
putting nalue of A in equation 1 we get
A+B=45
19+B=45
B=45-19
B=26
so number of 49 cent stamps are 19
and number of 33 cent stamps are 26
Answer:
Step-by-step explanation:
y = ax² + bx + c
~~~~~~~
(4, - 2), (8, 6), (2, 0)
a(4²) + b(4) + c = - 2
a(8²) + b(8) + c = 6
a(2²) + b(2) + c = 0
16a + 4b + c = - 2 .............. <em>(1)</em>
64a + 8b + c = 6 ............... <em>(2)</em>
4a + 2b + c = 0 ................. <em>(3)</em>
a = 0.5 ; b = - 4 ; c = 6
<em>y = 0.5x² - 4x + 6</em>
Part A: (0, 6), (6, 0)
Part B: (0,6)
Part C: (6, 0)
Part D: [ 4, ∞ )
