Monday's high temperature was six degrees Celsius the low temperature was -3°C

One ballispicked at random from a box containing 3redballs and 1green balls. If X is the number of redballs picked, find the pro

Paladinen [302]

Answer:

P(X = 0) = 0.25

P(X = 1) = 0.75

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The probability distribution of X.

3 red balls out of 4, one picked, so we can have either 0 red balls or 1 red ball. The probability disitribution is the probability of each outcome.

$P(X = 0) = \frac{1}{4} = 0.25$

$P(X = 1) = \frac{3}{4} = 0.75$

6 0

3 years ago

Let p =Vector F G where F(0, 5) and G(–4, –3). What is the direction angle of Negative three-halves p?

Harlamova29_29 [7]

Answer:

B

63 Degrees

Step-by-step explanation:

Edge 2020

3 0

3 years ago

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Las+salchichas+vienen+en+paquetes+de+6+y+los+panes+para+panchos+se+envasan+en+paquetes+de+8+unidades+¿Es+cierto+que+si+se+prepar

vovikov84 [41]

Answer:

Es cierto se usan 16 paquetes de salchichas y 12 paquetes de panes para pancho.

Step-by-step explanation:

Lo que debemos hacer en este caso es dividir la cantidad total de panchos primero por la cantidad de unidades de salchichas que vienen en su paquete y segundo por la cantidad de unidades de panes para panchos que vienen en su paquete, si el resultado nos da un numero entero podemos decir que usa una cantidad completa de paquetes de salchichas y de panes:

96/6 = 16

96/8 = 12

Es decir que para 96 panchos se usan 16 paquetes de salchichas y 12 paquetes de panes para pancho, por lo tanto es cierto.

8 0

3 years ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago

What is the length of this line? choose 1 answer 9 8 square root of 45 square root of 27

dedylja [7]

Step-by-step explanation:

αηѕωєя

6 0

3 years ago

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