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Paladinen [302]

3 years ago

5

Consider the function f(x) = x(x – 4). If the point (2 + cy) is on the graph of f(x), the following point will also be on the gr

aph of f(x): Select a Value Select a Value (C - 2,y) (2-cy)

1 answer:

kakasveta [241]3 years ago

3 0

Answer:

(2-cy) is the correct answer for the problem

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The length of a diagonal of a quadrilateral shaped field Is 48 m And the length of perpendicular dropped on it from the remainin

olchik [2.2K]

Answer:

$1008\text{ m}^2$

Step by step explanation:

Please find the attachment.

We have been given that the length of a diagonal of a quadrilateral shaped field Is 48 m. The length of perpendicular dropped on it from the remaining apposite vertices are 16 m and 26 m.

We can see from our attachment that diagonal AC divides our quadrilateral field into two triangular fields and AC will be the base of both triangles.

To find the area of our given quadrilateral we will find the areas of both triangles and add the areas.

Let us find area of triangle ABC with base 48 m and height 26 m.

$\text{Area of triangle}=\frac{1}{2}(\text{ Base}\times\text{ Height})$

$\text{Area of triangle ABC}=\frac{1}{2}\times 48\times 26$

$\text{Area of triangle ABC}=24\times 26$

$\text{Area of triangle ABC}=624$

Therefore, the area of triangle ABC will be 624 square meters.

Now let us find area of triangle ADC with base 48 m and height 16 m.

$\text{Area of triangle ADC}=\frac{1}{2}\times 48\times 16$

$\text{Area of triangle ADC}=24\times 16$

$\text{Area of triangle ADC}=384$

Therefore, the area of triangle ADC will be 384 square meters.

Now let us add areas of triangles ABC and ADC to get the area of our quadrilateral ABCD.

$\text{Area of quadrilateral ABCD}=384+624$

$\text{Area of quadrilateral ABCD}=1008$

Therefore, the area of quadrilateral shaped field will be 1008 square meters.

6 0

4 years ago

What would be the maximum value for f(x) = −5x2 + 9

Maru [420]

Well, looking at the expression, it has a -5 on the leading term, that means is not just a quadratic, but is a parabolic graph and because the coefficient of the leading term is negative, is upside-down, or opening downwards.

because it opens downwards, it looks like an arc, comes from the bottom up up up gets to a "maximum" or U-turn (vertex), then goes back down down down. So, where's the vertex anyway?

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
f(x) = &{{ -5}}x^2&{{ +0}}x&{{ +9}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{0}{2(-5)}~~,~~9-\cfrac{0}{4(-5)} \right)\implies (0~~,~~9)$

so, that's where the vertex is, and the maximum value for f(x), is the y-coordinate of course, or 9.

3 0

3 years ago

The measures of the angles in an equilateral triangle are equal.

JulijaS [17]

Answer:

c.60°

Step-by-step explanation:

A triangle has 3 angles. Sum of angles in a triangle is 180 degrees. Three angles of an equilateral triangle are equal

So 180/3 = 60

7 0

3 years ago

Give me a example of fractions

trapecia [35]

A fraction is something like 1/2 which is the same as half of one or 1/4 which is a fourth of one

5 0

3 years ago

What is the area of parallelogram RSTU? 21 square units 24 square units 28 square units 32 square units

Debora [2.8K]

Answer: 21 square units

Step-by-step explanation:

We know that the area of parallelogram is given by:-

$A=height\times base$

Let US denote the height of the Parallelogram RSTU with corresponding base ST.

By counting the distance between the points using grids or by distance formula,

US= $|4-(-3)|=|7|=7\ units$

ST= $|-1-(-4)|=|-1+4|=|3|=3\ units$

Now, the area of parallelogram RSTU is given by:-

$A=7\times3=21\ \text{square units}$

7 0

3 years ago

Read 2 more answers