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Arlecino [84]
3 years ago
5

Can anyone tell me how to do this?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer:

I'm too stoopid for this.

Step-by-step explanation:

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5 0
2 years ago
What are the solutions to x2 + 8x + 7 = 0? A. x = –8 and x = –7 B. x = –7 and x = –1 C. x = 1 and x = 7 D. x = 7 and x = 8
NikAS [45]

Answer:

x= -7      x = -1

Step-by-step explanation:

x^2 + 8x + 7 = 0

Factor

What 2 numbers multiply to 7 and add to 8

7*1 = 7

7+1 = 8

(x+7)(x+1) =0

Using the zero product property

x+7 =0   x+1 = 0

x= -7      x = -1

8 0
3 years ago
Read 2 more answers
The length of a rectangle is 3 more than 3 times its width. The perimeter of the rectangle is 174 inches. What is the length of
saveliy_v [14]

Answer:

<em>l = w + 3cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:</em>

I hope this helps you.

5 0
3 years ago
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