s=1/23
given equation in term of s is 12+3/2s-1/2-3/4s=5/4s
to solve this first we need to take LCM on left hand side and right hand side we can rewrite given equation as 12/1+3/2s-1/2-3/4s=5/4s now taking LCM of {1,2s,2,4s,4s} is 4s then the equation becomes 48s/4s+6/4s-2s/4s-3/4s=5/4s
(48s+6-2s-3) /4s=5/4s now cancel out denominator of both side we get 48s+6-2s-3=5 this implies 46s+3=5
46s=2
s=1/23
Hence the value of s is 1/23
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Answer:
The answer is 2.
Step-by-step explanation:
1- Suppose we have following array of ten integers: 5 3 8 9 1 7 0 2 6 4.
2- Before the last merge, the left half and the right half must be sorted. So it should be
1 3 5 8 9 0 2 4 6 7
Therefore the solution is 2.
Answer:
A. 0.186524036
Step-by-step explanation:
Cosine 79° 15'
But, 1° = 60'
Thus; 15' = 15/60 = 0.25°
Therefore;
cos 79° 15' = cos 79.25°
Cos 79.25° = 0.186524036
= 0.186524036
the answer is C................................
25 because Becky read 45 and Jason read 20
45-20 = 25
